Answer:
The 99% confidence interval for p in this case is (0.3317, 0.5883).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
Randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students.
This means that:
99% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for p in this case is (0.3317, 0.5883).
