keeping in mind that when the logarithm base is omitted, the base 10 is assumed.
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%3D2%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D2%5Cimplies%2010%5E2%3Dx%5Cimplies%20100%3Dx)
numerator. Denominator is what the numerator fits into
The question is incomplete. Here is the complete question.
Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.
a) Determine the arc length to the nearest tenth of an inch.
b) Explain why the following proportion would solve for the length of AC below: 
c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.
Note: The image in the attachment shows the arc to solve this question.
Answer: a) 9.4 in
c) x = 13.6 in
Step-by-step explanation:
a)
, where:
r is the radius of the circumference
mAB is the angle of the arc
arc length = 
arc length = 
arc length = 9.4
The arc lenght for the image is 9.4 inches.
b) An <u>arc</u> <u>length</u> is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):


c) Resolving (b):
x = 
x = 13.6
The arc length for the image is 13.6 inches.
You will need 27 quarters.
1.25*3= 3.75
3.75+3= 6.75
There are 4 quarters in a dollar. 6 dollars = 24 quarters, plus 3 more quarters to equal the .75
For the answer to the question above, If you've noticed, the statement mentioned "a number". Let's assign x to be the number. The first statement is twice a number (2x). Then, decreased by the quotient of that number and 2 (-x/2). Lastly, the statement at least 12 is written as >12.
So the answer is
2x - (x/2) >12