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Vladimir [108]
3 years ago
6

What is the distance between A and B? Round your answer to the nearest tenth. A coordinate plane is shown. Point A is located at

negative 1, 5, and point B is located at 4, 1. A line segment connects the two points. 6.4 7.3 8.2 9.1
Mathematics
1 answer:
o-na [289]3 years ago
3 0
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ 1}}\quad ,&{{ 5}})\quad 
%  (c,d)
B&({{ 4}}\quad ,&{{ 1}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
AB=\sqrt{(4-1)^2+(1-5)^2}\implies AB=\sqrt{3^2+(-4)^2}
\\\\\\
AB=\sqrt{9+16}\implies AB=\sqrt{25}\implies AB=5
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Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

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Take the square root of each side

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Add 2 to each side

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Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

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15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

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Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

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Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

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