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Cloud [144]
3 years ago
6

I have done 14 projects so far, and gotten 100% on all of them.

Mathematics
1 answer:
mariarad [96]3 years ago
5 0
100x14=1400
1400 divided by 15=93.3
So your grade would still be a low A
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A research center project involved a survey of 846 internet users. It provided a variety of statistics on internet users. (a) Th
I am Lyosha [343]

Answer:

(a) (0.9240,  0.956)

(b) (0.6383, 0.7017)

Step-by-step explanation:

The number of internet users involved in the survey, n = 846

The percentage of the respondents that said the internet has been good thing for them personally, \hat p = 94%

(a) The confidence interval of a percentage is given as follows;

CI=\hat{p}\pm z\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

The z-value for 95% confidence interval = 1.96

We get;

CI=0.94\pm 1.96\times \sqrt{\dfrac{0.94 \times (1-0.94)}{846}} \approx 0.94 \pm 1.6003 \times 10^{-2}

CI = 0.9240 ≤ \hat p ≤ 0.956 = (0.9240,  0.956)

(b) The percentage of the internet users that said the internet has directly strengthened their relationship with their families, \hat p = 67% = 0.67

The 95% confidence interval is therefore;

CI=0.67\pm 1.96\times \sqrt{\dfrac{0.67 \times (1-0.67)}{846}} \approx 0.67 \pm 3.1686\times 10^{-2}

From which we have;

CI = 0.6383 ≤ \hat p ≤ 0.7017 = (0.6383, 0.7017)

5 0
3 years ago
What is the discriminant of the quadratic equation
kkurt [141]
The discriminant is  b^2 -4ac
a = 1
b = -2
c = 4

discriminant = 4 -4 * 1 * 4 =
4  -16 =
 -12
I get MINUS 12 as the answer but that isn't one of the choices.





7 0
3 years ago
Rewrite the number in standard form.6.15 x 102<br> a. 61,500<br> b. 615<br> c. 600<br> d. 0.0615
mina [271]

Answer:B

Step-by-step explanation:

8 0
3 years ago
The length of a rectangular poster is 9 more inches than half its width. The area of the poster is 72 square inches. Solve for t
Kipish [7]

The dimensions of the rectangle will be 6 inches and 12 inches.

<h3>What is the area of the rectangle?</h3>

Let L be the length and W be the width of the rectangle.

Then the area of the rectangle will be

Area of the rectangle = L × W square units

The length of a rectangular poster is 9 more inches than half its width.

L = W/2 + 9

The area of the poster is 72 square inches. Then we have

72 = L × W

72 = (W/2 + 9) × W

144 = (W + 18) × W

144 = W² + 18W

W² + 18W - 144 = 0

Then the factor of the equation will be

W² + 18W - 144 = 0

W² + 24W - 6W - 144 = 0

W(W + 24) - 6(W + 24) = 0

(W + 24)(W - 6) = 0

W = -24, 6

The width of the rectangle is 6 inches. Then the length of the rectangle will be

L = 6/2 + 9

L = 3 + 9

L = 12 inches

The dimensions of the rectangle will be 6 inches and 12 inches.

More about the area of the rectangle link is given below.

brainly.com/question/20693059

#SPJ1

4 0
2 years ago
(x^3+43-49x-7x^2)/(x^2-49)
GaryK [48]
(X-7) is an answer and -300 is the reminder
7 0
4 years ago
Read 2 more answers
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