In general 2^n is the number of pieces of information n bits can store.
(a) Antonio can use the formula 2^n-1 to indicate the maximum size of numbers an n-bit word can store.
(b) for a 16-bit system, the maximum number of keys Millie can collect is 2^(16)-1 = 65536-1=65535
(c) For a 14 byte program, there are 14*8=112 bits.
Answer:
f(x) = 7/(x+3) -38/(x+3)²
Step-by-step explanation:
The denominator is a perfect square, so the decomposition to fractions will involve both a linear denominator and a quadratic denominator.
You can start with the form ...
... f(x) = B/(x+3) + A/(x+3)²
and write this sum as ...
... f(x) = (Bx +3B +A)/(x+3)²
Equating coefficients gives ...
... Bx = 7x . . . . . B = 7
... 3B +A = -17 . . . . the constant term
... 21 +A = -17 . . . . filling in the value of B
... A = -38 . . . . . . . subtract 21 to find A
Now, we know ...
... f(x) = 7/(x+3) -38/(x+3)²
Answer:
They are parallel.
Step-by-step explanation:
They have the same slope, 7, and different y-intercepts, 4, -1/4, so they are parallel.
first number and second number and third number = Total
78 possibilities x 78 possibilities x 78 possibilities = 234
Since "order" matters, this is a permutation.
So, this can be calculated using: ₇₈P₃
"Permutation lock" would be a more appropriate name.
