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Andrews [41]
3 years ago
11

Solve 42 div 3 using an area model

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0
What's area model ? ☺☺☺☺
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Find the 31st term of the sequence 12,16,20
Natali [406]

Answer:

136

Step-by-step explanation

multiply 4 by 31 and add 20

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3 years ago
Write an equation for the translation of y = |x| and the translation is up 4 right 2.
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<span> y = |x-2|+4

it is a negative 2 because you do the inverse</span>
8 0
4 years ago
What is the GFC of 40 and 60
Svetradugi [14.3K]

Answer:

GCF: 20

Step-by-step explanation:

The thing you want to do is factor both numbers down to their lowest primes.

40:2 * 2 * 2 * 5

60:2 * 2 * 5 * 3

Now underline what is in both sets of primes. I'll bold them. The number that is bolded comes from 2 * 2 * 5 which is 20

The highest common factor is 20

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3 years ago
Pleaseee helppppp !!
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Answer:

1. -9xy

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Step-by-step explanation:

4 0
3 years ago
A box contains 8 two-inch screws. Four have a Phillips head and 4 have a slotted head. In how many ways can 4 screws be chosen s
hammer [34]

Answer:

There are 6\cdot 6=36 different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

Step-by-step explanation:

If 4 screws must be chosen so that 2 have a Phillips head and 2 have a slotted head, then you have to choose 2 screws with a Phillips head from 4 screws with a Phillips head and 2 screws with a slotted head from 4 screws with a slotted head.

You can choose 2 screws with a Phillips head from 4 screws with a Phillips head in

C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6

different ways.

You can choose 2 screws with a slotted head from 4 screws with a slotted head in

C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6

different ways.

In total there are 6\cdot 6=36 different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

7 0
3 years ago
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