Ask question

Ask question

All categories

3 years ago

11

Solve 42 div 3 using an area model

1 answer:

ololo11 [35]3 years ago

5 0

What's area model ? ☺☺☺☺

You might be interested in

Ms. Gadget car broke down on the turnpike. Acme town Ig charged $30 plus $3 per mile to tow the car. If ms. Gadget paid $162, ho

Reil [10]

The equation would be 30+3m=162 then you solve the problem

4 0

2 years ago

The daily calorie intake for a rider in the Tour de France is 3500 calories. If the race for the day is 4 hours, about how many

stepan [7]

Answer:

875 calories per hour

Step-by-step explanation:

To find out how much calories would be used per hour you have to divide 3500 calories by 4 hours to get 875 calories. Hope this helps :)

4 0

3 years ago

What is the answer to 1/4N=24

PilotLPTM [1.2K]

0.25*N=24
N=24/0.25
N=96

8 0

3 years ago

Read 2 more answers

How to justify a/b x b/c = a/c?

jeyben [28]

A/b times b/c is = ab/bc
which can be written as a/c times b/b
anything over itself is 1 so b/b is one
a/b times b/c = a/c

8 0

3 years ago

Read 2 more answers

Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =

DanielleElmas [232]

Answer:

$c = 5$

Step-by-step explanation:

Given

$f(c) = M$

$f(x) = x^2 - x + 1$

$Interval: [1,8]$

$M = 21$

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

$f(x) = x^2 - x + 1$

$f(1) = 1^2 - 1 + 1$

$f(1) = 1$

$f(x) = 8^2 - 8 + 1$

$f(x) = 57$

$1 \le M \le 57$

$1 \le 21 \le 57$

M is within range.

Solving further:

We have:

$f(c) = f(x) = M$

$f(x) = 21$

Substitute 21 for f(x) in $f(x) = x^2 - x + 1$

$21 = x^2 - x + 1$

Express as quadratic function

$x^2 - x + 1 - 21 = 0$

$x^2 - x - 20 = 0$

Expand

$x^2 + 4x - 5x - 20$

$x(x+4)-5(x+4)=0$

$(x - 5)(x+4) = 0$

$x - 5 = 0$ or $x + 4= 0$

$x = 5$ or $x = -4$

The value of $x = -4$ is outside the $Interval: [1,8]$

So:

$x = 5$

$f(c) = f(x) = M$

$f(c) = f(5) = 21$

By comparison:

$c = 5$

4 0

3 years ago