r = distance of moon from earth = 3.84 x 10⁸ m
R = size of the object on moon = 0.67 m
D = diameter of the lens = ?
= wavelength of light = 550 x 10⁻⁹ m
Using the equation for Rayleigh criterion
R/r = 1.22
/D
inserting the values
0.67/(3.84 x 10⁸) = 1.22 (550 x 10⁻⁹) /D
D = 384.6 m
Answer:
80 ft/s
Explanation:
Given:
Δy = 100 ft
v₀ = 0 ft/s
a = 32.2 ft/s²
Find: v
v² = v₀² + 2aΔx
v² = (0 ft/s)² + 2 (32.2 ft/s²) (100 ft)
v = 80.2 ft/s
Rounded, the speed when it reaches the ground is 80 ft/s.
higher frequency/shorter wavelength
OR
carries more energy than red light.
The third one because it is a small one and it had high and high temp so it has the most modecules.
Hope this helps
Answer:
F = 8840.7 N
Explanation:
The parameters given are:
Length L = 3 metres
Extension e = 3 × 3 = 9m
Force constant K = 982.3 Newton per metre
From Hook's law,
Provided the elastic limit is not extended, the extension is directly proportional to the force applied.
That is,
F = Ke
Substitute all the parameters into the formula
F = 982.3 × 9
F = 8840.7 N