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Snezhnost [94]
3 years ago
11

A scientist in Northern California is studying the tree rings of a very old redwood tree. He notices that the oldest tree rings

are very narrow. As the rings move away from the center, he observes 15 rings that get wider and wider.
What can you determine about the climate during the 15-year period during which the tree rings grew wider?

The climate was warmer and wetter.
The climate was warmer and drier.
The climate was colder and drier.
The climate was colder and wette
Physics
2 answers:
Studentka2010 [4]3 years ago
5 0

Answer: colder and drier

Explanation:

Trees don’t grow well in wet climates, nor when they are cold. The wider the rings, the healthier the tree is. Since it was narrow and then wide, was bad climate and then good.

natali 33 [55]3 years ago
3 0

Answer:

A

Explanation:

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A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi
vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

V=\frac {C_2V_2-C_1V_1}{C_1+C_2}

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}

Therefore

V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437

Charge, Q is given by CV hence for the first capacitor charge will be Q_1=C_1V

Here, Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C

8 0
3 years ago
The correctly balanced equation for H2O2 → H2O + O2 is
Citrus2011 [14]

Answer:2H2O2 → 2H2O + O2

Explanation:

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As we can see that we now have 4 moles of Hydrogen and 4 moles of oxygen at both reactant and product making the equation balanced.

8 0
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If a person whirls an object horizontally in a counter clockwise direction and the string breaks at point P as shown, what path
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when an object is revolving in circular path then its velocity is always along the tangent of the circular path

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So here also the object will move along its tangential direction once the string will break

so here the correct path will be

Option B

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