Answer:
The maximum height of the ball is 2 m.
Explanation:
Given that,
Mass of ball = 50 g
Height = 1.0 m
Angle = 30°
The equation is

We need to calculate the velocity
Using conservation of energy

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

Put the value into the formula

Put the value into the formula




We need to calculate the maximum height of the ball
Using again conservation of energy

Here, h = y highest point
Put the value into the formula



Put the value of y in the given equation




Hence, The maximum height of the ball is 2 m.
C) The president submits the federal budget every year.
Hope this helps you!
Answer:
1.25 m
0.5 s
Explanation:
Given:
v₀ = 5 m/s
v = 0 m/s
a = -10 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (5 m/s)² + 2 (-10 m/s²) Δy
Δy = 1.25 m
Find: t
v = at + v₀
(0 m/s) = (-10 m/s²) t + (5 m/s)
t = 0.5 s
1) The grapefruit is in free fall, so it moves by uniformly accelerated motion, with constant acceleration

. Calling h its height at t=0, the height at time t is given by

We are told thatn when

the grapefruit hits the ground, so h(0.75 s)=0. If we substitute these data into the equation, we can find the initial height h of the grapefruit:


2) The speed of the grapefruit at time t is given by

where

is the initial speed of the grapefruit. Substituting t=0.75 s, we find the speed when the grapefruit hits the ground:
Answer:
a. 0.15 kg m2
b. 19.8 rad/s
Explanation:
Metric unit conversion:
10 cm = 0.1 m
5 cm = 0.05 m
a. Using parallel axis theorem, the rotational inertia of the cylinder about the axis of rotation is the inertia about the longitudinal axis plus the product of mass and distance from the longitudinal axis to the rotational axis squared

whereas the inertia about the longitudinal axis of the solid cylinder is



b. Assume the cylinder does not rotate about its own longitudinal axis, we can treat this as a point mass pendulum. So when it's being released from 0.05m high (release point) to 0m (lowest position), its potential energy is converted to kinetic energy:


where h = 0.05 is the vertical distance traveled, v is the cylinder linear velocity at the lowest position.g = 9.81m/s2 is the gravitational acceleration.
We can divide both sides by m



The angular speed is linear speed divided by the radius of rotation, which is distance from the cylinder center to the center of rotation d = 0.05 m
