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Arada [10]
3 years ago
14

If x is a number that is 7 more than y, how do you express x as a function of y?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

answer is e

hope.it helps

plz mark as brainliest

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Evaluate 5+ when each number is placed in the box
polet [3.4K]

Answer:

6. 8

7. 10

8. 29

Step-by-step explanation:

6. 3+5

7. 5+5

8. 24+5

4 0
3 years ago
State the property or properties of logarithms used to rewrite the expression.
Korvikt [17]

Answer:

The answer is option A.

<h3>Power Property and Product </h3><h3>Property</h3>

Hope this helps you

6 0
2 years ago
Which number is represented by point E on the graph?
zavuch27 [327]

Answer:

It'll be -0.25

Step-by-step explanation:

Notice how it is to the left of zero, anything to the left of zero is negative. With that in mind, we can eliminate A. The half mark between 0 and -1 represents 0.50, and since it goes by quarters, the E is at the first quarter, which is 0.25. Hopefully this helps!

7 0
3 years ago
Read 2 more answers
He vertices of square pqrs are p -4,0 q 4,3 r 7,-5 and s -1,-18.Show that the diagonals of square pqrs are congruent perpendicul
Anit [1.1K]

Answer:

Step-by-step explanation:

The vertices of the square given are P(-4, 0), Q(4, 3), R(7, -5) and, S(-1, -18)

For this diagonal to be right angle the slope of the diagonal must be m1=-1/m2

So let find the slope of diagonal 1

The two points are P and R

P(-4, 0), R(7, -5)

Slope is given as

m1=∆y/∆x

m1=(y2-y1)/(x2-x1)

m1=-5-0/7--4

m1=-5/7+4

m1=-5/11

Slope of the second diagonal

Which is Q and S

Q(4, 3), S(-1, -18)

m2=∆y/∆x

m2=(y2-y1)/(x2-x1)

m2=(-18-3)/(-1-4)

m2=-21/-5

m2=21/5

So, slope of diagonal 1 is not equal to slope two

This shows that the diagonal of the square are not diagonal.

But the diagonal of a square should be perpendicular, this shows that this is not a square, let prove that with distance between two points

Given two points

(x1,y1) and (x2,y2)

Distance between the two points is

D=√(y2-y1)²+(x2-x1)²

For line PQ

P(-4, 0), Q(4, 3)

PQ=√(3-0)²+(4--4)²

PQ=√(3)²+(4+4)²

PQ=√9+8²

PQ=√9+64

PQ=√73

Also let fine RS

R(7, -5) and, S(-1, -18)

RS=√(-18--5)+(-1-7)

RS=√(-18+5)²+(-1-7)²

RS=√(-13)²+(-8)²

RS=√169+64

RS=√233

Since RS is not equal to PQ then this is not a square, a square is suppose to have equal sides

But I suspect one of the vertices is wrong, vertices S it should have been (-1,-8) and not (-1,-18)

So using S(-1,-8)

Let apply this to the slope

Q(4, 3), S(-1, -8)

m2=∆y/∆x

m2=(y2-y1)/(x2-x1)

m2=(-8-3)/(-1-4)

m2=-11/-5

m2=11/5

Now,

Let find the negative reciprocal of m2

Reciprocal of m2 is 5/11

Then negative of it is -5/11

Which is equal to m1

Then, the square diagonal is perpendicular

6 0
3 years ago
Share £480 in the ratio 2:3:7
aleksandr82 [10.1K]
£480

2:3:7 =  2+3+7  = 12

 2
--- 0f £480 = £80
12


 3
--- of £480 = £120
12

 7
--- of £480 = £280
12


answer =  £80 : £120 : £280
5 0
3 years ago
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