1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
avanturin [10]
3 years ago
7

If the outliers are not included, what is the mean of the data set? 76, 79, 80, 82, 50, 78, 83, 79, 81, 82 (2 points) Select one

: a. 77 b. 78 c. 79 d. 80
Mathematics
1 answer:
wlad13 [49]3 years ago
6 0
Hello!

As you can see, 50 is the outlier, as it is not around the other numbers in the data set. Therefore, we will calculate the mean of all the numbers if we add up all the numbers and divide by 9.

(76+79+80+82+78+83+79+81+82)÷9=80

The mean of this data set (excluding the outlier) is 80.

I hope this helps!
You might be interested in
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
Degger [83]

Answer:

So do you already have the answer? Also 1/20 looks right.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A study of peach trees found that the average number of peaches per tree was 725. The standard deviation of the population is 70
TEA [102]

Answer:

She needs to sample 189 trees.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation of the population is 70 peaches per tree.

This means that \sigma = 70

How many trees does she need to sample to obtain an average accurate to within 10 peaches per tree?

She needs to sample n trees.

n is found when M = 10. So

M = z\frac{\sigma}{\sqrt{n}}

10 = 1.96\frac{70}{\sqrt{n}}

10\sqrt{n} = 1.96*70

Dividing both sides by 10:

\sqrt{n} = 1.96*7

(\sqrt{n})^2 = (1.96*7)^2

n = 188.2

Rounding up:

She needs to sample 189 trees.

3 0
3 years ago
Rearrange to make x the subject<br> 4(x-3) =y<br> pls help
Alina [70]
4(-3x)=y F f f f f f f f d d d d d d d d d d d d d d d d d d d d d d
3 0
2 years ago
I need help right away ASAP!!!Please help me please finding the missing angle
german

\\ \sf\longmapsto tan\Theta=\dfrac{P}{B}

\\ \sf\longmapsto tan40=\dfrac{48}{x}

\\ \sf\longmapsto 0.8=\dfrac{48}{x}

\\ \sf\longmapsto 0.8x=48

\\ \sf\longmapsto x=\dfrac{48}{0.8}

\\ \sf\longmapsto x=60

8 0
2 years ago
Read 2 more answers
So im really confused by this and could use some help.
Otrada [13]

Answer:

Nancy fits the equation.

Step-by-step explanation:

I think they're asking which gorilla fits the equation.

2b - 15 = 605

<em>Add 15 to both sides</em>

2b=620

<em>Divide both sides by 2</em>

b=310

The only gorilla who weighs 310 pounds is Nancy.

5 0
3 years ago
Other questions:
  • Frank and Dwayne weed their gardens that are the same size. Frank's garden is divided into 6 equal sections. Dwayne's garden is
    9·1 answer
  • ? of 72 = 45 (answer in fraction)
    14·1 answer
  • An advertiser that uses ad scheduling has a custom bid adjustment for 9pm- 12am on weeknights. The normal bid is USD$0.40 and th
    8·1 answer
  • A shirt is on sale for 3/5 off of the regular price of $10
    8·2 answers
  • What is area of this
    7·1 answer
  • 5x 2 - 8+ 4SOMEONE HELP PLS AND THANK U:)!!
    14·1 answer
  • Find the midpoint of the segment with the following endpoints.<br> (7, -2) (1, -10)
    12·2 answers
  • Need help if want points.<br>choose your answer​
    10·1 answer
  • Which expression is equivalent to z+(z+6)?
    12·1 answer
  • A map has a scale of 1 inch = 6 miles. How many miles are 3 inches
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!