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Minchanka [31]
3 years ago
7

Show that (3m+4n)2 –48mn= (3m-4n)2

Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

9m2+16n2+24mn-48mn

9m2+16n2-24mn

(3m-4n)2

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Answer:

Max\ Area = \frac{x^2}{16}

Step-by-step explanation:

Given

P = x ---- the perimeter of fencing

Required

The maximum area

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W \to Width

So, we have:

P = 2(L + W)

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Substitute L = \frac{x}{2} - W

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Open bracket

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Differentiate with respect to W

A' = \frac{x}{2} - 2W

Set to 0

\frac{x}{2} - 2W = 0

Solve for 2W

2W = \frac{x}{2}

Solve for W

W = \frac{x}{4}

Recall that:

L = \frac{x}{2} - W

L = \frac{x}{2} - \frac{x}{4}

L = \frac{2x- x}{4}

L = \frac{x}{4}

So, the maximum area is:

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Answer:

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Step-by-step explanation:

10 × $500

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3 years ago
Read 2 more answers
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