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Sloan [31]
3 years ago
11

A company will need 40,000 in 6 years for a new addition. To meet the goal, the company deposits money into an account today tha

t pays 4% annual intrest compund quarterly.
Mathematics
1 answer:
NeTakaya3 years ago
3 0
"<span>A company will need 40,000 in 6 years for a new addition. To meet the goal, the company deposits money into an account today that pays 4% annual intrest compund quarterly."  Let's pretend that the instructions state, "Determine the amount of money that must be deposited upfront so that you will have $40,000 in 6 years."

Use the Compound Amount formula:  A = P(1 + r/n)^(nt),
where P is the principal (the amount deposited upfront), r is the interest rate as a decimal fraction, n is the number of compounding periods, and t is the time in years.

Here, $40000 = P(1 + 0.04/4)^(4*6)
                                                               $40000
So the upfront $ needed is      P =   -------------------------
                                                           (1+0.01)^24

This comes out to $31502.65 (answer)</span>
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Shkiper50 [21]

Answer:

infinite

Step-by-step explanation:

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6 0
2 years ago
Read 2 more answers
Evaluate if x=4<br> 3x+1<br><br> A)2<br> B)3<br> C)11/4<br> D)13/4
mariarad [96]

Step-by-step explanation:

Given

If x = 4 Then

3x + 1 = 3 * 4 +1 = 12 + 1 = 13

The answer should be 13.

4 0
2 years ago
Refer to the isosceles trapezoid shown. Find m(BC)
patriot [66]

Answer:

answer is 9cm

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hopes this helps u

5 0
3 years ago
How would you write a decimal that is less than five Ten thousandths
asambeis [7]

Five ten-thousandths looks like this:  0.0005

All of these are less:

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etc.

3 0
3 years ago
Find m c to the nearest tenth if c=48 a=34 m
Brut [27]
C=48
a=34m

m=a/34

m*c=48*a/34=48a/34=24a/17
7 0
2 years ago
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