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4 years ago

Multi-step Factoring Factor completely. 27 – 48x^4

Mathematics

1 answer:

Setler [38]4 years ago

5 0

27-48x^4= 3(9-16x^4)

Because 3 is the GCF

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How to find the steeper slope in a graph?

Sauron [17]

Answer:

When you look at the two lines, you can see that the blue line is steeper than the red line. It makes sense the value of the slope of the blue line, 4, is greater than the value of the slope of the red line, . The greater the slope, the steeper the line.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

**URGENT** PLEASE HELP WILL GIVE BRAINLIEST

Gnoma [55]

Answer:

they are both 0 since they would not appear on a graph

Step-by-step explanation:

6 0

3 years ago

Write the vertex form of the equation of the parabola which has a vertex of (0,0) and contains the point (2,-2)

Anettt [7]

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
y=a(x-{{ h}})^2+{{ k}}\qquad 
\begin{cases}
h=0\\
k=0
\end{cases}\implies y=a(x-0)^2+0
\\\\\\
y=ax^2\qquad 
\begin{cases}
x=2\\
y=-2
\end{cases}\implies -2=a2^2$

solve for "a", to get the coefficient, and then plug it back in the equation.

7 0

4 years ago

Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels at 95 miles per

alisha [4.7K]

Answer:

It will take 1.6 hours for the two trains to be 336 miles apart.

Step by step explanation:

Given that:

Speed of eastbound train = 95 miles per hour

Speed of westbound train = 115 miles per hour

Combined speed = 95+115 = 210 miles

Distance = 336 miles

$Speed = \frac{Distance}{Time}\\\\210 = \frac{336}{Time}\\\\Time = \frac{336}{210}\\\\Time = 1.6\ hours$

Hence,

It will take 1.6 hours for the two trains to be 336 miles apart.

3 0

3 years ago

Determine the amplitude and period of each function without graphing.

Luba_88 [7]

Answer:

Step-by-step explanation:

We know for a function:

y = Asinωt

=> on comparison, <u>A = 5 m</u>

=> T = 2π / ω

=> T = 2π / 2

=> <u>T = π seconds</u>

5 0

2 years ago