Answer:
0.057 M
Explanation:
Step 1: Given data
Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴
Concentration of mercury (II) ion: 0.085 M
Step 2: Write the reaction for the solution of HgBr₂
HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻
Step 3: Calculate the bromide concentration needed for a precipitate to occur
The Ksp is:
Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²
[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M
The answer for the given question above is IONIC. <span>Ionic substances form giant ionic </span>lattices<span> containing oppositely charged ions. They have high melting and boiling points, and </span>conduct<span> electricity when melted or dissolved in water.</span>
Answer:
1. Nonmetals.
2. Likely to form anions (except the noble gases).
3. All of these
4. Easily reduced (except the noble gases).
Explanation:
Elements with high electronegativities are found towards the upper right corner of the Periodic Table. Thus, they have all the above properties.
Answer:
Explanation:
n CaCO3 = mass / m.wt
= 500 /( 40 + 12 + 16x 3)
= 5 mole
n CaO = 5 moles ( from the balanced equation we have 1:1 moles )
mass of CaO = nCaO X m.wt
5 x( 40 +16 )
= 280 grams