The polynomial with a GCF of 5z is 5z * (x + 1) and the equivalent form is 5xz + 5z and 5xz + 4z + z
<h3>How to create the polynomial?</h3>
From the question, we have the GCF of the polynomial to be:
GCF = 5z
So, we represent the polynomial as follows:
Polynomial = GCF * Other factor
Substitute the known values in the above equation
Polynomial = 5z * Other factor
Let the other factor be x + 1
So, we have:
Polynomial = 5z * (x + 1)
Expand the polynomial
Polynomial = 5xz + 5z
Hence, the polynomial with a GCF of 5z is 5z * (x + 1) and the equivalent form is 5xz + 5z and 5xz + 4z + z
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Answer:
I don't think there is a remainder for this problem
Step-by-step explanation:
type "0"
Answer:
Step-by-step explanation:
8)Volume of cylinder = πr²h= π*3*3*10 =90π cubic inches
Volume of cone = 1/3πr²h = π*3*3*5/3= 15π cubic inches
Volume of rocket = 90π + 15π = 105π cubic inches
9) Matt made an error. radius = diameter/2 = 15/2= 7.5 cm.Instead using 7.5 in volume formula, he used diameter.
Answer:
a = 4
Step-by-step explanation:
Assuming you require to find the value of a
In a rhombus all the sides are congruent, thus
9a - 13 = 3a + 11 ( subtract 3a from both sides )
6a - 13 = 11 ( add 13 to both sides )
6a = 24 ( divide both sides by 6 )
a = 4
Then
XW = 9a - 13 = 9(4) - 13 = 36 - 13 = 23
Thus the sides of the rhombus are 23 units