<span>Vaccines help develop immunity by imitating an infection. but it does cause the immune system to produce T-lymphocytes and antibodies. Sometimes, after getting a vaccine, the imitation infection can cause minor symptoms, such as fever.</span>
Complete question:
Thinking creatively about evolutionary mechanisms, identify at least
two schemes that could generate allelic polymorphism in a population except natural selection that favors heterozygotes.
<u>Select the two correct answers.</u>
-inbreeding among individuals in the population
-purifying selection against mutational variants of alleles in the population
-continuous migration of individuals with new alleles into the population
-mutations that do not severely affect viability and reproductivity
-genetic drift of alleles common in the population
-events leading to genetic bottleneck effect
Answer:
The two events that might favor heterozygotes among the options are
- The Continuous migration of individuals with new alleles into the population
- Mutations that do not severely affect viability and reproductivity. These might favor heterozygous frequencies.
Explanation:
Due to technical problems, you will find the complete explanation in the attached files.
Answer:
Option (A) and (D).
Explanation:
Esophagus may be defined the long tube like structure that connect the throat with the stomach. The partially digested food from the buccal cavity to the stomach is pass down through the esophagus.
The mucosa of the esophagus contains the thick layer of the nonkeratinized squamnous epithelium. The smooth muscles are present in some layers only. The two layer of the muscle that are superior to the one third of the muscularis are the skeletal muscle.
Thus, the correct answer is option (A) and (D).
Answer:
Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.
One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.
Then,
The number of Barr bodies with Klinefelter would be:
Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.
Similarly, for
Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)
Now, as per the question, the bar bodies for karyotypes given
47,XYY: (n-1) = (1-1) = 0 Barr bodies
47,XXX: (n-1) = (3-1) = 2 Barr bodies
48,XXXX: (n-1) = (4-1) = 3 Barr bodies
