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UNO [17]
3 years ago
6

HELP HELP!!

Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

0

Step-by-step explanation:

p_1:~~y = x^2+2\\p_2:~~y = 3x^2+2\\ \\ V{p_1} = \Big(-\dfrac{b}{2a}, -\dfrac{\Delta}{4a}\Big) = \Big(-\dfrac{0}{2}, -\dfrac{0^2-4\cdot 2}{4}\Big) = \Big(0,2\Big) \\ \\ Vp_2 = \Big(x_V, -\dfrac{\Delta}{4a}\Big) = \Big(0, -\dfrac{0^2-4\cdot 3 \cdot 2}{4\cdot 3}\Big) = \Big(0,2\Big) \\ \\ \\ \text{The distance is }0,~~\text{Because the vertices are equal.}

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Find the value of X so that the function has the given value t(x)=3x; t (x)= 24
Fed [463]

Answer:

here is your answer....

Step-by-step explanation:

lets take x as 8

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8 0
3 years ago
2
rusak2 [61]

Answer:

(1.13, 7.74) and (-4.13, 18.26)

Step-by-step explanation:

This can be solved in two ways:  mathematically and graphically.

<u>Graphing</u>

Plot both lines and find where they intersect.  See the attachment.

The intersection points are (1.13, 7.74) and (-4.13, 18.26)

<u>Mathematical</u>

y + 2x = 10

y = 10 - 2x

y = 3x² + 7x - 4

10 - 2x = 3x² + 7x - 4

3x² + 9x - 14 = 0

Solve this using the quadratic equation:

x = 1.13 and -4.13

Use these two values of x to find y:

y = 10 - 2x

y = 10 - 2(1.13)

y = 7.74

y = 10 -2x

y = 10 -2(-4.13)

y =  18.26

The two points are:

(1.13, 7.74) and (-4.13, 18.26)

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2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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