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svetoff [14.1K]
3 years ago
9

Rewrite the following equation in standard form. y + 2 = -8(x + 6)

Mathematics
1 answer:
crimeas [40]3 years ago
8 0

Answer:

y=-8x-50

Step-by-step explanation:

Standard form or slope intercept form is y=mx+b  

m=slope or (y2-y1/x2-x1) or rise/run

b= y-intercept or where the graph of the equation crosses the y-axis

So we have;

y+2=-8(x+6)

y=-8(x+6)-2

y=-8x-48-2

y=-8x-50

Any questions please feel free to ask. Thanks.

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Jlenok [28]

Step-by-step explanation:

This is a linear equation in slope intercept form which is

y = mx + b

where m is the slope and b is the y intercept.

The equation

y =  -  \frac{1}{3} x + 2

Has a slope of -1/3 so this means that the slope will be decreasing. A negative linear equation increases as we go left. and decreases as we go right. The y intercept is 2. So this means the graph must pass through (0,2) and when x=0, y must be 2.

In other words, look for a line that the y values increase as we go left and decrease we go right. Also look for a point (0,2) and make sure the graph pass through it.

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Solve for x.<br> -x/3=2<br><br> x= -6<br> x= -1<br> x = 6
LenKa [72]

Answer:

x = -6

Step-by-step explanation:

Solve for x:

-x/3 = 2

Multiply both sides of -x/3 = 2 by -3:

(-3 (-x))/3 = -3×2

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(-3 (-1))/3 x = -3×2

(-3)/3 = (3 (-1))/3 = -1:

--1 x = -3×2

(-1)^2 = 1:

x = -3×2

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Answer:  x = -6

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FOR BRAINLIEST ANSWER HURRY HELP THANKS If (a,b) is a point in quadrant IV, what must be true about a? What must be true about b
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Answer:

Well if (a,b) is in Quadrant IV which is the last quadrant the a or x is a positive number and the b or y is a negative number.

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Forty students are In Science club. Of those 45% are girls. This percent increase 56% after new girls join the club. How many ne
stepan [7]
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