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IgorLugansk [536]
4 years ago
10

Which coordinate pair fits the set of coordinates {(0, 4), (-2, 1), (-4, -2)} defined by a linearfunction?

Mathematics
1 answer:
dedylja [7]4 years ago
6 0

Answer:

y = 1.5x + 4

Step-by-step explanation:

Slope = (y2-y2)/(x2-x1)

= (1-4)/(-2-0) = -3/-2 = 3/2

y = (3/2)x + c

When x=0, y=4 (y-intercept is 4)

y = (3/2)x + 4

y = 1.5x + 4

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Select all the expressions equivalent to (4x⁵)(5x⁶).
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Step-by-step explanation:

= 4 {x}^{5}  \times 5 {x}^{6}

= (4 \times 5) {x}^{5 + 6}

= 20 {x}^{11}

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3 years ago
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The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains poi
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Answer:

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4 0
2 years ago
Read 2 more answers
The set of ordered pairs represents a
Murrr4er [49]

Answer:

The rule that represents the function is y=x^2+1 therefore the function is f(x)=x^2+1

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We have 5 ordered pairs in the plane xy. This means that <em>every pair has the form (x, y).</em>

Then, we have 5 values of x, which will give us 5 values of y, using the rule that represents the function.

<u>The easy evaluation is that when x=0, the value of y is y=1,</u> and then we can evaluate the rule for x=-1, and x=1, <em>the value of y is the same, y=2</em>. We can see here that we have a parabolic function, that is not centered in the origin of coordinates because when x=0, y=1.

So <u>we propose the rule </u>y=x^2+1<u> which is correct for the first 3 values of x.</u>

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Therefore, the rule is correct, and the function is

f(x)=x^2+1

8 0
3 years ago
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