Answer:
The reaction quatient Q is 0.306
Explanation:
Step 1: data given
Volume = 2.50 L
Temperature = 1100 K
Number of moles C = 6.75 moles
Number of moles H2O = 13.5 moles
Number of moles CO = 3.10 moles
Number of moles H2 = 9.00 moles
Step 2: The balanced equation
C(s)+H2O(g)⇌CO(g)+H2(g)
Step 3: Calculate the concentration
Concentration = moles / volume
[C] = 6.75 moles / 2.5 L
[C] = 2.7 M
[H20] = 13.5 moles / 2.5 L
[H2O] = 5.4 M
[CO] = 3.10 moles / 2.5 L
[CO] = 1.24 M
[H2] = 9.00 moles / 2.5 L
[H2]= 3.6 M
Step 4: Calculate Q
Q = [CO][H2] / [C][H2O]
Q = (1.24 * 3.6)/(2.7*5.4)
Q = 0.306
The reaction quatient Q is 0.306
Answer:
T₂ = 687.6 K
Explanation:
Given data:
Initial pressure = 108 Kpa
Initial temperature = 20°C
Final temperature = ?
Final pressure = 2.50 atm
Solution:
Initial pressure = 108 Kpa = 108/101 = 1.06588 atm
Initial temperature = 20°C = 20+273.15 = 293.15 k
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
1.06588 atm / 293.15 K = 2.5 atm/T₂
T₂ = 2.5 atm ×293.15 K / 1.06588 atm
T₂ = 732.875 atm. K /1.06588 atm
T₂ = 687.6 K
Answer:
The third reaction
(2NaOH + NiCL2 ---> 2NaCl + Ni(OH)2)
Explanation:
By definition, a precipitation reaction refers to the formation of an insoluble salt when two solutions containing soluble salts are combined.
(Source: lumenlearning)
From the 4 options, we can eliminate the first and second one immediately because there is no formation of an insoluble salt.
Then, the last one can also be eliminated because even though there is insoluble solid formed, but it is not a salt, and, the reactants are not solutions too. In fact, the last one is a displacement reaction. A more reactive metal displaces a less reactive metal to form an ion.
Since the third reaction matches the definition of precipitation reaction, this is the answer.