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guajiro [1.7K]
3 years ago
5

An electron moved from a lower energy level to a higher energy level. What most likely happened during the transition?

Chemistry
2 answers:
hichkok12 [17]3 years ago
6 0

Answer:

The correct answer is statement that a fixed amount of energy was absorbed.

Explanation:

In an atom, the electrons prevail in distinct energy levels. The electrons present in an atom are confined to a particular level of energy, which is located at different distances from the nucleus. The electrons, which are in the highest energy level are known as valence electrons. Inside every energy level lies a space volume where particular electrons are situated.  

The energy is absorbed by the atom when an electron moves to a higher energy level from a lower energy level, and the energy is discharged when an electron moves to a lower energy level from a higher energy level in the form of light.  

nekit [7.7K]3 years ago
5 0

Answer:

Amount of energy was released

Explanation:

Because when energy is release from the shell it makes the electron lose and than go to higher level of energy form

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The picture shows a contractile vacuole of a unicellular freshwater organism. The contractile vacuole regulates the flow of wate
yuradex [85]

Answer:

A.The concentration of water is greater outside the cell than inside the cell.

Explanation:

The contractile vacuole of certain organisms functions to regulate water flow in and out of the cell. It does this by storing excess water that comes into the cell. In the case of this organism with a filled up contractile vacuole, it means water is flowing into the cell.

Naturally, water will flow into a living cell when an osmotic gradient i.e. difference in concemtration, has been created between intracellular and extracellular solutions. Osmosis involves movement of substances from a region of high water concentration to a region of low water concentration. This means that if water is flowing into the cell, which is stored by the contractile vacuole, the concentration of water must be greater outside the cell than inside.

6 0
3 years ago
An element has an average atomic mass of 1.008 amu. It consists of two isotopes , one having a mass of 1.007 amu, and one having
dimulka [17.4K]

Answer:

The most abundant isotope is 1.007 amu.

Explanation:

Given data:

Average atomic mass = 1.008 amu

Mass of first isotope = 1.007 amu

Mass of 2nd isotope = 2.014 amu

Most abundant isotope = ?

Solution:

First of all we will set the fraction for both isotopes

X for the isotopes having mass  2.014 amu

1-x for isotopes having mass 1.007 amu

The average atomic mass is 1.008 amu

we will use the following equation,

2.014x + 1.007  (1-x) = 1.008  

2.014x + 1.007  - 1.007 x = 1.008  

2.014x - 1.007x  =  1.008  -  1.007

1.007 x = 0.001

x= 0.001/ 1.007

x= 0.0009

0.0009 × 100 = 0.09 %

0.09 % is abundance of isotope having mass  2.014 amu because we solve the fraction x.

now we will calculate the abundance of second isotope.

(1-x)

1-0.0009 = 0.9991

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6 0
3 years ago
After the recycled plastic is released from the machine into the brick mold, explain what will happen to the kinetic energy in t
Rina8888 [55]

Answer: Depending on the data and the patterns, sometimes we can see that pattern in a simple tabular presentation of the data. Other times, it helps to visualize the data in a chart, like a time series, line graph, or scatter plot.

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8 0
3 years ago
The half-life of sr-90 is 28 years. after 56 years of decay only 0. 40 g of a sample remains. what was the mass of the original
Svetradugi [14.3K]

Half-life is the time taken for the concentration of the substance to reduce by 50%. The original sample of strontium had a mass of 1.6 gms. Thus, option d is correct.

<h3>What is half-life?</h3>

The half-life of any radioactive substance is the time period at which the concentration will get reduced to half the initial amount. The initial mass of Sr-90 is calculated as,

N(t) = N_{0} (\dfrac{1}{2})^{ \frac{t }{t 1/2}}

Given,

Quantity of the remaining substance N (t) = 0.40 gm

Initial radioactive substance quantity N_{0} =?

Time duration (t) = 56 years

Half-life = 28 years

Substituting values above:

\begin{aligned} 0.40 &= N_{0} (\dfrac{1}{2}) ^{{\frac{56}{28}}\\\\0.40 &= N_{0} (\dfrac{1}{2})^{2}\end{aligned}

= 1.6 gm

Therefore, option d. the initial mass of Sr is 1.6 gm.

Learn more about half-life here:

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