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dusya [7]
3 years ago
14

what is the volume of a book that has a width of 10cm,a length that is 2 times the width,and a height that is half the width​

Chemistry
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

1000cm^3

Explanation:

first collect what is known

width 10cm

length 2×width (2×10cm) =20cm

height width/2 (10cm/2) =5cm

now if we use the formula for finding volume of a cuboid that has length, width and height known;

V = l×w×h

= 20cm × 10cm × 5cm

= 1000cm^3

Masteriza [31]3 years ago
5 0

width=10cm

length=2xwidth=2x10=20cm

height=width/2=10/2=5

V=w*l*h=10*20*5=1000cm^3

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Yes,this is an example:
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3 years ago
Caffeine (C8H10N4O2) is a weak base with a pKb of 10.4. Calculate the pH of a solution containing a caffeine concentration of 41
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Answer:

pH → 7.47

Explanation:

Caffeine is a sort of amine, which is a weak base. Then, this pH should be higher than 7.

Caffeine + H₂O  ⇄  Caffeine⁺  +  OH⁻      Kb

1 mol of caffeine in water can give hydroxides and protonated caffeine.

We convert the concentration from mg/L to M

415 mg = 0.415 g

0.415 g / 194.19 g/mol = 2.14×10⁻³ mol

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Let's calculate pH. As we don't have Kb, we can obtain it from pKb.

- log Kb = pKb → 10^-pKb = Kb

10⁻¹⁰'⁴ = 3.98×10⁻¹¹

We go to equilibrium:

Caffeine + H₂O  ⇄  Caffeine⁺  +  OH⁻      Kb

Initially we have 2.14×10⁻³ moles of caffeine, so, after the equilibrium we may have (2.14×10⁻³ - x)

X will be the amount of protonated caffeine and OH⁻

     Caffeine     +    H₂O  ⇄  Caffeine⁺  +  OH⁻      Kb

   (2.14×10⁻³ - x)                         x                x

We make the expression for Kb:

3.98×10⁻¹¹ = x² / (2.14×10⁻³ - x)

We can missed the -x in denominator, because Kb it's a very small value.

So: 3.98×10⁻¹¹ = x² / 2.14×10⁻³

√(3.98×10⁻¹¹ . 2.14×10⁻³) = x → 2.92×10⁻⁷

That's the [OH⁻].  - log [OH⁻] = pOH

- log 2.92×10⁻⁷ = 6.53 → pOH

14 - pOH = pH → 14 - 6.53 = 7.47

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3 years ago
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Answer: 28000m/s

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6 0
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