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dusya [7]
3 years ago
14

what is the volume of a book that has a width of 10cm,a length that is 2 times the width,and a height that is half the width​

Chemistry
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

1000cm^3

Explanation:

first collect what is known

width 10cm

length 2×width (2×10cm) =20cm

height width/2 (10cm/2) =5cm

now if we use the formula for finding volume of a cuboid that has length, width and height known;

V = l×w×h

= 20cm × 10cm × 5cm

= 1000cm^3

Masteriza [31]3 years ago
5 0

width=10cm

length=2xwidth=2x10=20cm

height=width/2=10/2=5

V=w*l*h=10*20*5=1000cm^3

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What is the concentration of a dextrose solution prepared by diluting 16 mL of a 1.0 M dextrose solution to 25 mL using a 25 mL
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Answer:

0.64 M

Explanation:

Step 1: Given data

  • Initial concentration (C₁): 1.0 M
  • Initial volume (V₁): 16 mL
  • Final concentration (C₂): ?
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Step 2: Calculate the final concentration of the dextrose solution

We want to prepare a diluted solution from a concentrated one. We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 1.0 M × 16 mL / 25 mL

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Balance each of the following redox reactions occurring in basic solution.MnO−4(aq)+Br−(aq)→MnO2(s)+BrO−3(aq)Express your answer
Ahat [919]

Answer : The balanced chemical equation is,

2MnO_4^-(aq)+Br^-(aq)+H_2O(l)\rightarrow 2MnO_2(s)+BrO_3^-(aq)+2OH^-(aq)

Explanation :

Rules for the balanced chemical equation in basic solution are :

  • First we have to write into the two half-reactions.
  • Now balance the main atoms in the reaction.
  • Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
  • If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
  • If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion (OH^-) at that side where the less number of hydrogen are present.
  • Now balance the charge.

The half reactions in the basic solution are :

Reduction : MnO_4^-(aq)+2H_2O(l)+3e^-\rightarrow MnO_2(s)+4OH^-(aq) ......(1)

Oxidation : Br^-(aq)+6OH^-(aq)\rightarrow BrO_3^-(aq)+3H_2O(l)+6e^-  .......(2)

Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

2MnO_4^-(aq)+Br^-(aq)+H_2O(l)\rightarrow 2MnO_2(s)+BrO_3^-(aq)+2OH^-(aq)

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