The statement 'a crocodile-like animal is the ancestor of birds' is BEST supported by the information in the table (option A).
- Evolution refers to the biological process of descendence with modification.
- Evolutionary close species share functional and structural phenotypic features due to a same-origin during evolution.
- A crocodile is a reptile, and it has been shown that birds evolved from theropod dinosaurs (reptile).
In conclusion, the statement 'a crocodile-like animal is the ancestor of birds' is BEST supported by the information in the table (option A).
Learn more in:
brainly.com/question/599077
Answer:
a) 9%.
b) 16.8%.
Explanation:
a).
We are provided with the information that Two linked genes, A and B, are separated by 18 cM (centiMorgan). i.e the recombinant frequency is 18%
Also , the man's genotype is AB/ab... This only result to one explanation, that The man will definitely produce 18% of recombinant gametes which entails
9% Ab & 9% aB
i.e 0.09 Ab & 0.09 aB
On the other-hand, The mother ab/ab have tendency to produce just one single type of gamete which is ab
∴
The probability that their first child will be Ab/ab will be
Pr ( Ab/ab) = (0.09) x (1)
= 0.09
= 9%.
b).
If the father produces 18% of recombinant gametes which entails
9% Ab & 9% aB , this typically implies that the number of the non-recombinant gametes will be;
100%-18% = 82% ( non-recombinant gametes)
i.e genotype AB/ab = 82%
AB =41%; ab = 41%
AB = 0.41 ; ab = 0.41
Now, the probability that their first two children will both be ab/ab:
Using Multiplication Rule to calculate the probability that their first two children (ab/ab); we have:
(0.41)(1) ×(0.41)(1)
= 0.1681
= 16.8%.
Answer:
The genotype of the parents are not given. Let's try to answer this question generally. Let's assume the genotype of both parents to be Bb as genotype is not given.
Explanation:
B b
B BB Bb
b Bb bb
There is a 25% chance that the offspring will have BB genotype.
There is a 50% chance that the offspring will have Bb genotype.
There is a 25% chance that the offspring will have bb genotype.
There is a 75% chance that the offspring will have a dominant trait.
There is a 25% chance that the offspring will have recessive trait.
Phenotypic ratio will be 3:1
PDK1 (pyruvate dehydrogenase kinase 1) is an enzyme which inactivates the pyruvate dehydrogenase by phosphorylating it using an ATP molecule<span>.
</span><span>PDK1 (phosphoinositide-dependent protein kinase-1) acts by catalyzing the phosphorylation of Thr-229 (threonine at position 229 in pyruvate dehydrogenase).
This phosphorylation is </span><span>synergistic</span> with the phosphorylation of C-terminal Thr-389, but this one is not done by the PDK1.
