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2 years ago

8-2x=5-4x 4+3x=2-2x 2(x-1)+2(3x-1)=0

Mathematics

2 answers:

vodka [1.7K]2 years ago

8 0

Answer:

See the below part

Step-by-step explanation:

8 - 2x = 5 - 4x

=> 8 - 5 = -4x + 2x

=> 3 = -2x

=> 3/-2 = x

=> -3/2 = x

4 + 3x = 2 - 2x

=> 4 - 2 = -2x - 3x

=> -2 = -5x

=> 2 = 5x

=> 2/5 = x

2(x - 1) + 2(3x - 1) = 0

=> 2x - 2 + 6x - 2 = 0

=> 8x - 4 = 0

=> 8x = 4

=> x = 4/8

=> x = 1/2

Murrr4er [49]2 years ago

3 0

The answer for the first and the second one

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32%

Step-by-step explanation:

Given

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3 years ago

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3 years ago

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Q.8 What is the tail length?

Arlecino [84]

If I'm correct you should make a fraction first
5.4 3.6
----- to -----
4.8 ?

Now find the missing number
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3 years ago

A scientist is studying the growth of a particular species of plant. He writes the following equation to show the height of the

Savatey [412]

Answer:

(A) The reasonable domain to plot the growth function is (0 ≤ n < 5).

(B) The y-intercept of the function is 10 cm. It represents the height of the plant at the beginning of the experiment.

Step-by-step explanation:

The equation representing the height of the plant is:

$f (n)=10\cdot (1.02)^{n}$

(A)

It is provided that at the end of the study the height of the plant was approximately 11.04 cm.

Compute the range of values of n as follows:

$f (n)=10\cdot (1.02)^{n}\\11.04 = 10\cdot(1.02)^{n}\\1.104 = 1.02^{n}\\\ln (1.104) = \ln (1.02^{n})\\\ln (1.104) = n \ln (1.02)\\\\n = \frac{\ln (1.104)}{ \ln (1.02)}\\\\n = 4.99630409516\\n\approx 5$

Thus, the reasonable domain to plot the growth function is (0 ≤ n < 5).

(B)

The y-intercept, in this case would represents the height of the plant when they began the experiment.

That is, the y-intercept of the function is the value of f (n) for n = 0.

Compute the value of f (n = 0) as follows:

$f (0)=10\cdot (1.02)^{0}=10$

Thus, the y-intercept of the function is 10 cm. It represents the height of the plant at the beginning of the experiment.

(C)

Compute the values of f (n = 1) and f (n = 5) as follows:

$f (1)=10\cdot (1.02)^{1}=10.2\\\\f (5)=10\cdot (1.02)^{5}=11.0408\approx 11.04$

Compute the average rate of change as follows:

$\text{Average rate of change}=\frac{f(n_{2})-f(n_{1})}{n_{2}-n_{1}}$

$=\frac{11.04-10.20}{5-1}\\\\=\frac{0.84}{4}\\\\=0.21$

Thus, the average rate of change of the function f(n) from n = 1 to n = 5 is 0.21.

The average rate of change is known as the slope of the function. The slope represents how much the plant is growing every day.

Thus, the slope of 0.21 implies that the plant is growing 0.21 cm every day.

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