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PilotLPTM [1.2K]
3 years ago
9

PLLLLLLLLLZ HELP 30 POINTS ANSWER ONLY IF YOU KNOW

Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

  R^2 = 40^2 + 70^2 - 2(40)(70) cos 135°

Explanation:

The resultant connects the tail of the first vector to the head of the second vector (whose tail is at the head of the first vector). The three vectors form an obtuse triangle where the angle between the original direction and the second direction is 135°. The cosine factor in the Law of Cosines formula will be cos(135°), matching the second choice.

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A cliff diver from the top of a 100 (m) cliff. He begins his dive by jumping up with a velocity of 5 (m/s) a. How
Nutka1998 [239]

Answer:

A.) 4.81 seconds

B.) 44.6 m/s

Explanation:

He begins his dive by jumping up with a velocity of 5 (m/s).

Let us first calculate the maximum height reached by using third equation of motion

V^2 = U^2 - 2gH

At maximum height, V = 0

0 = 5^5 - 2 × 9.8H

19.6H = 25

H = 25 /19.6

H = 1.28 m

The time taken for the diver to reach the water from the maximum height can be calculated by using second equation of motion.

Where height h = 1.28 + 100 = 101.28 m

h = Ut + 1/2gt^2

As the diver drop from maximum height, U = 0

101.28 = 1/2 × 9.8 × t^2

4.9t^2 = 101.28

t^2 = 101.28/4.9

t^2 = 20.669

t = sqrt ( 20.669)

t = 4.55s

As the diver jumped up, the time taken to reach the maximum height will be

Time = 1.28 / 5 = 0.256

The time taken for him to hit the water below will be 0.256 + 4.55 = 4.81 seconds

B.) Velocity right before he hits the water will be

V^2 = U^2 + 2gH

But U = 0

V^2 = 2 × 9.8 × 101.28

V^2 = 1985.09

V = 44.6 m/s

6 0
4 years ago
A spotlight on the ground shines on a wall 12m away. If a man 2m tall walks from the spotlight toward a building at a speed of 1
exis [7]
<span> we suppose that x be distance of man from spot light is
so 12-x is distance from man to wall
we will draw first triangle ABC, where
a= spotlight (on ground)
b= man (feet)
c= man (head)
we know that AB = x and BC = 2
by extend line AB to the wall at point D and extend line AC to the wall at point E
AD = 12 (distance from spotlight to wall)
DE = s (length of shadow)
Now triangles ABC and ADE are similar
Therefore DE/AD = BC/AB
s / 12 = 2 / x
s = 24 / x
Differentiate both sides with respect to t
ds/dt = -24/x² dx/dt
Man is walking toward building at speed of 16 ms
dx/dt = 16
Man is 4 m from the building/wall
12 - x = 4
x = 8
Find ds/dt when x = 8 and dx/dt = 16
ds/dt = -24/x² dx/dt
ds/dt = -24/(64) * 16
ds/dt = -6

So length of shadow is decreasing at rate of 6 m/s
hope it helps
</span>
4 0
4 years ago
Wind blows to where there is a higher..
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Temperature.........
6 0
3 years ago
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Compared with those who live in the lowlands, people who live in the Southeast highlands experience​
Alisiya [41]

Answer:

The territory of Scotland was divided into two parts -- the highlands and the lowlands.

Explanation:

The people living in places of high altitudes are called highlanders. These high altitude places are called high lands and places with low elevations or altitudes are called the low lands. There are many differences between the two places and people experiences different difficulties in these places.

Some of the differences are :

The life of the people living in high lands are much more tougher than those living in the low lands. The highlanders have to work more hard than lowlanders.

The agricultural activities are more flourished in the low lands than in the high lands.

The low lands are more populated and highly industrialized than the high lands. Iron and steel industry, metal working industry and agriculture are some of the main industries of lowlands. They are the land of the Scottish nation.

6 0
3 years ago
Would time move slower or faster approaching black hole?
Mars2501 [29]
Slower towards the black hole
5 0
3 years ago
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