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3 years ago

How much tension does it take to snap someone's neck?

2 answers:

3 0

To break<span> the </span>neck<span> of a human, ~ 1,250 foot-pounds of torque is required. And this is without the person's resistance.</span>

alexdok [17]3 years ago

3 0

Answer:

To break the neck of a human, 1,000 to 1,250 foot-pounds of torque is considered sufficient. When hanging someone, a typical drop of 5 to 9 feet is enough to generate the force required to break the neck when the person hits the end of the rope.

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An ideal gas is compressed at constant pressure p=1500 Pa from a volume Vi=0.4 m3 to Vf=0.25 m3. At the same time, heat is trans

Anon25 [30]

To solve this problem we will apply the first law of thermodynamics and we will make a balance between the heat transferred, its internal energy and the total work. Recall that for gases the definition of work can be expressed in terms of its pressure and volume. Let's start

$dQ = dU +dW$

Here,

dU = Internal Energy

dW = Work

But internal energy is unchanged, then

$dQ = dW$

$dQ = PdV$

Where

$dV$ = Change in Volume

P = Pressure

Finally, the expression of the heat transferred can be expressed in terms of pressure and volume, so it would end up becoming

$dQ = p(v_i-v_f)$

Replacing,

$dQ = (1500)(0.4-0.25)$

$dQ = 225J$

Therefore the correct answer is B.

3 0

4 years ago

7. You start to walk toward the east towards home at a constant speed of 4 km/hr. At the same time, Someone else leaves your hom

amm1812

A) position time graph for both is shown

here one of the graph is of lesser slope which means it is moving with less speed while other have larger slope which shows larger speed

At one point they intersects which is the point where they both will meet

B) Let the two will meet after time "t"

now we can say that

if they both will meet after time "t"

then the total distance moved by you and other person will be same as the distance between you and home

so it is given as

$v_1t + v_2t = d$

$4*t + 28*t = 3.2 km$

$t = \frac{3.2}{32} = 0.1 hr$

so they will meet after t = 6 min

so from position time graph we can see that two will meet after t = 6 min where at this position two graphs will intersect

4 0

4 years ago

What is the most effective way to prevent beach erosion?

sergiy2304 [10]

The most effective way to prevent beach erosion is to replant mangrove trees, seaweeds and seagrass. The strategic planting of vegetation can be used to help control erosion. The roots of these plants help to anchor the sand and ensure that it is not carried off in erosion. This is why many areas plant seagrass and build marshes along coasts to prevent erosion.

8 0

4 years ago

A racing car travels with a constant tangential speed of 80.8 m/s around a circular track of radius 602 m. (a) Find the magnitud

KatRina [158]

Answer:

10.84 m/s2 radially inward

Explanation:

As the car is traveling an a constant tangential speed of 80.8 m/s, the total acceleration only consists of the centripetal acceleration and no linear acceleration. The formula for centripetal acceleration with respect to tangential speed v = 80.8 m/s and radius r =602 m is

$a = \frac{v^2}{r} = \frac{80.8^2}{602} = 10.84 m/s^2$

b) The direction of this centripetal acceleration is radially inward

6 0

4 years ago

Calculate the magnitude of the gravitational force exerted by the Moon on a 79 kg human standing on the surface of the Moon. (Th

Luden [163]

Answer:

F= 134.92 N

Explanation:

Given that

The mass of the moon ,M = 7.4 x 10²² kg

The mass of the man ,m = 79 kg

The radius ,R= 1.7 x 10⁶ m

The force exerted by moon is given as

$F=G\dfrac{Mm}{R^2}$

Now by putting the values in the above equation we get

$F=6.67\times 10^{-11}\times \dfrac{79\times 7.4\times 10^{22}}{(1.7\times 10^6)^2}\ N\\F=134.92 N$

Therefore the force will be 134.92 N.

F= 134.92 N

8 0

4 years ago