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3 years ago

How much tension does it take to snap someone's neck?

2 answers:

3 0

To break<span> the </span>neck<span> of a human, ~ 1,250 foot-pounds of torque is required. And this is without the person's resistance.</span>

alexdok [17]3 years ago

3 0

Answer:

To break the neck of a human, 1,000 to 1,250 foot-pounds of torque is considered sufficient. When hanging someone, a typical drop of 5 to 9 feet is enough to generate the force required to break the neck when the person hits the end of the rope.

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A bullet of mass 0.017 kg traveling horizontally at a high speed of 290 m/s embeds itself in a block of mass 5 kg that is sittin

rodikova [14]

Answer:

(a) vf = 0.98 m/s

(b) K₁ = 714.85 J : Total translational kinetic energy before the collision.

K₂= 2.41 J : Total translational kinetic energy after the collision.

Explanation:

Theory of collisions

Linear momentum is a vector magnitude (same direction of the velocity) and its magnitude is calculated like this:

p=m*v

where

p:Linear momentum

m: mass

v:velocity

There are 3 cases of collisions : elastic, inelastic and plastic.

For the three cases the total linear momentum quantity is conserved:

P₀ = Pf Formula (1)

P₀ :Initial linear momentum quantity

Pf : Final linear momentum quantity

Data

m₁ = 0.017 kg : mass of the bullet

m₂ = 5 kg : mass of the block

v₀₁ = 290 m/s : initial velocity of the bullet

v₀₂ = 0 : initial velocity of the block₂

(a) Speed of the block after the bullet embeds itself in the block

We appy the formula (1):

P₀ = Pf

m₁*v₀₁ + m₂*v₀₂ = (m₁+ m₂)vf

vf: final velocity of the block

( 0.017)*( 290) + (5)*(0) = ( 0.017 + 5 )*vf

4.93+ 0 = ( 5.017 )*vf

vf = 4.93 / 5.017

vf = 0.98 m/s

b) Total translational kinetic energy before (K₁) and after the collision(K₂).

K₁ = 1/2(m₁*v₀₁² + m₂*v₀₂²)

K₁ = 1/2(0.017*(290)² + 5*(0)²) = 714.85 J

K₂= 1/2(m₁+ m₂)*vf²

K₂= 1/2(0.017+ 5)*(0.98)² = 2.41 J

6 0

3 years ago

I need help by today guys plz help

NISA [10]

radio waves bc they have the longest wave lenthgs in a magnetic spectrum

5 0

3 years ago

_________ acceleration occurs when an object speeds up.

Angelina_Jolie [31]

Positive acceleration occurs when an object speeds up.

Explanation:

Acceleration is the rate of change in velocity per unit time:

$a=\frac{\Delta v}{\Delta t}$

where $\Delta v$ is the change in velocity while $\Delta t$ is the time interval. From the formula, we can understand that when $\Delta v$ is positive, so when the object is speeding up, the acceleration is positive; on the contrary, when $\Delta v$ is negative (so, when the object is slowing down), the acceleration is negative.