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7nadin3 [17]
3 years ago
6

The relationship among speed, distance, and time is

Physics
2 answers:
Ivenika [448]3 years ago
6 0
Velocity or speed= distance/time

alexdok [17]3 years ago
3 0
Distance= speed (multiplied by) time
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Can kintic friction affect mechanical energy
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Yes. Kinetic energy is a form of mechanical energy and friction will turn that kinetic energy into heat.
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3 years ago
During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t
tia_tia [17]

1.A) 4.9 m  

AL2006 Ace

The instant it was dropped, the ball had zero speed.


After falling for 1 second, its speed was 9.8 m/s straight down (gravity).


Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.


Falling for 1 second at an average speed of 4.9 m/s, is covered 4.9 meters.


ANYTHING you drop does that, if air resistance doesn't hold it back.


Read more on Brainly.com - brainly.com/question/11776597#readmore

2 idk sorry

5 0
3 years ago
Read 2 more answers
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one
Fittoniya [83]
I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= AC-AB = 7.7-5 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = -6.25/5.4 = -1.157 so acceleration is -1.157m/(s^2)
8 0
3 years ago
Read 2 more answers
A 10 kg cart is rolling across a parking lot with a velocity of .5 m/s. What is its momentum?
-Dominant- [34]

Hello!

\large\boxed{p = 5  \text{ } kgm/s}

Use the equation for momentum:

p = mv

Plug in the given mass and velocity into the equation:

p = 10 * 0.5

p = 5 kgm/ s

4 0
2 years ago
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