helped discover elements down the line
The balance chemical equation is as follow,
2 Al + 3 O₂ → Al₂O₃
Aluminium is the Limiting Reagent,
As,
107.92 g Al required = 96 g of O₂
Then,
82.49 g of Al will require = X g of O₂
Solving for X,
X = (82.49 g × 96 g) ÷ 107.92 g
X = 73.37 g of O₂
But,
We are provided with 117.65 g of O₂, So, it is provided in excess and 44.28 g of it will remain unreacted.
Solving for Amount of Al₂O₃ formed,
As,
107.92 g of Al produced = 203.92 g of Al₂O₃
Then,
82.49 g of Al will produce = X g of Al₂O₃
SOlving for X,
X = (82.49 g × 203.92 g) ÷ 107.92
X = 155.86 g of Al₂O₃
Answer:
1. 67.2 kJ/mol
Explanation:
Using the derived expression from Arrhenius Equation

Given that:
time
= 8.3 days = (8.3 × 24 ) hours = 199.2 hours
time
= 10.6 hours
Temperature
= 0° C = (0+273 )K = 273 K
Temperature
= 30° C = (30+ 273) = 303 K
Rate = 8.314 J / mol
Since 
Then we can rewrite the above expression as:








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Answer:
<h2>0.02 moles </h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have

We have the final answer as
<h3>0.02 moles</h3>
Hope this helps you