The given solution of Mn²⁺ is 0.60 mg/mL.
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg
Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol
The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺
The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5
Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
= 13.65 x 10⁻⁵ mol
Molar mass of KIO₄ = 230 g/mol
Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
= 0.031395 g
= 31.395 mg
≈ 31.4 mg
Protons = 20
Electron = 20
Neutrons = 20
Hope this Helps :)
The Law of conservation of mass states that option C: matter is neither created nor destroyed.
<h3>What is the law of conservation of matter?</h3>
Physical and chemical changes can cause matter to transform into different forms, but no matter what happens, matter is always conserved. There is no creation or destruction of matter; the amount of matter is the same before and after the transformation.
The principle of matter conservation. argues that matter cannot be generated or destroyed during a chemical reaction. The same number of atoms exist before and after the alterations even though the matter may shift from one form to another. reactant.
Therefore, According to the principle of mass conservation, neither chemical processes nor physical changes can create or destroy mass in an isolated system. The mass of the products and reactants of a chemical reaction must be equal, in accordance with the law of conservation of mass.
Learn more about matter from
brainly.com/question/3998772
#SPJ1
See full question below
1. Multiple-choice
Q.
Conservation of matter article questions
Law of conservation of mass states that
answer choices
matter is created
matter is destroyed
matter is neither created nor destroyed
matter does not change
360 seconds?
i’m guessing that is the answer as the question is unreasonable
Answer:
129,600kg/day
Explanation:
The river is flowing at 30.0
1 m³ is equivalent to 1000L
flowrate of river = 30*1000 =30,000L/s
Convert L/s to litre per day by multiplying by 24*60*60
flowrate of river = 30,000 * 24*60*60 L/day
= 2,592,000,000L/day
if the river contains 50mg of salt in 1L of solution
lets find how many mg of salt Y is contained in 2,592,000,000L/day
by cross multiplying we have
Y=
Y= 129,600,000,000 mg/day
convert this value to kg/day by dividing by 1 million
Y= 129,600,000,000/1000000
Y= 129,600kg/day
