Answer:
Mass of NaBr produced = 23.67 g
Explanation:
Given data:
Mass of AgBr = 42.7 g
Mass of NaBr produced = ?
Solution:
Chemical equation:
2Na₂S₂O₃ + AgBr → NaBr + Na₃(Ag(S₂O₃)₂
Number of moles of AgBr:
Number of moles = mass/molar mass
Number of moles = 42.7 g/ 187.7 g/mol
Number of moles = 0.23 mol
now we will compare the moles of AgBr with NaBr.
AgBr : NaBr
1 : 1
0.23 : 0.23
Mass of NaBr:
Mass = number of moles × molar mass
Mass = 0.23 mol × 102.89 g/mol
Mass = 23.67 g
FeS + H₂O → FeO + H₂S
Explanation:
Iron Sulfide = FeS
Water = H₂O
FeS + H₂O → FeO + H₂S
To balance this equation, we can use a mathematical method. This involves solving simple algebraic equations
aFeS + bH₂O → cFeO + dH₂S
a,b,c and d are the coefficients needed to balance up the equation:
Conserving Fe: a = c
S: a = d
H: 2b = 2d
O: b = c
let a = 1, c= 1, b = 1 d = 1
The balanced equation is: FeS + H₂O → FeO + H₂S
learn more:
Balanced equation brainly.com/question/2612756
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