Hello from MrBillDoesMath!
Answer:
x > -7/3
Discussion:
-3x + 8 < 15 => add 3x to both sides
(-3x + 3x) + 8 < 15 + 3x => (-3x + 3x) = 0
8 < 15 + 3x => subtract 15 from both sides
8-15 < 3x => 8 - 15 = -7
-7 < 3x => divide both sides by 3
-7/3 < x
Thank You,
MrB
Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,

Hence, this is the required solution.
Question (18):
Answer: (A) All of the following
(I am using
in place of conj(z)

Question (19):
Answer: (B) -7
modulus of -7 is sqrt(49)=7
the other choices are all < 7
Answer:
1/12
Hope this helps!
I got C for 6 & 7. I haven't done this in a while so I don't know 8 & 9. I hope I helped!