How do i find LM? On number 2 .

Mathematics

1 answer:

Masja [62]4 years ago

4 0

Given: KL is a tangent to the circle.
LM is another tangent to the circle.

We can use the tangent meeting at an external point theorem.
Theorem: The tangent segments to a circle from an external point are equal.

Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.

4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5

Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18

Thus, LM = KL = 18 units.

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Anton [14]

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3 years ago

Could someone explian to me how to do these two? i’m not sure if i’m doing it right plz help

omeli [17]

Step-by-step explanation:

Before I discuss how to graph both equations, I believe that it is essential to understand the variables and constant related to linear equations.

The slope-intercept form is: y = mx + b, where:

m = slope (which tells you the steepness of the line).

b = y-intercept: this is the point on the graph where it crosses the y-axis. Its coordinates is always formatted as, (0, b). The b is the y-coordinate of the y-intercept that you use for the equation.

The standard form of linear equations is: Ax + By = C, where:

A, B, C are integers (whole numbers, and cannot be in fraction or decimal forms). A and B ≠ 0, and A must be a positive integer.

Now that I have defined what the slope-intercept and standard form of linear equations are, we can proceed with working on graphing both equations.

In this equation, the slope (m) = -6, and the y-intercept (b) = -4. As an ordered pair, the y-intercept is (0, -4). In order to graph this equation, start by plotting the y-intercept on the graph. Then, use the slope (rise over run) to plot other points on the graph (6 units down, 1 unit run). Your next point should occur at (1, -10).

You could simply connect these two points and draw a line, or plot another point on the graph using the slope technique mentioned in this post.

This equation is in standard form, Ax + By = C. It is easier to graph a linear equation when it is in its slope-intercept form, y = mx + b.

In order to transform this equation into its slope-intercept form, start by subtracting 3x from both sides of the equation:

3x - 4y = 12

3x - 3x - 4y = - 3x + 12

-4y = -3x + 12

Next, divide both sides by -4 to isolate y:

$\frac{-4y}{-4} = \frac{-3x + 12}{-4}$

y = ¾x - 3 ⇒ This is the slope-intercept form where the slope, m = ¾, and the y-intercept is b = -3.

Similar to how we graphed the equation from question 7, start by plotting the y-intercept, (0, -3). Then, use the slope of the equation, m = ¾ (3 units rise, 4 units run) to plot the next point. The next point should occur at (0, 4).

Attached are the graphed equations.