298 x 0.062 = the amount that is deducted
298 x 0.062 = 18.476
The total amount of money she has earned this year is given to you just to confuse you. All you really need is the percent converted to a decimal, which is 0.062, and her weekly pay, which is $298. You multiply these two together to get 18.476, which when rounded becomes $18.48.
So, every week, $18.48 is deducted from her weekly pay.
Answer:
during
Step-by-step explanation:
During the evening, my parents expect me to wash the dishes and do my homework.
a preposition tells you when or where it happened
during is telling you when it happened
Answer:
87
Step-by-step explanation:
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
Answer
True
Step-by-step explanation:
