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2 years ago

SHOW WORK PLEASE IN A TESt!!!

Mathematics

1 answer:

charle [14.2K]2 years ago

4 0

Add 10 to both sides to cancel out the 10
divide 2 on both sides
X= 18

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Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

2 years ago

Which pair of terms are like terms?

sdas [7]

Answer:

b: -2y and 4y

Step-by-step explanation:

The answer is option B

-2y and 4y are like terms because they have the same algebraic alphabet at the back of their coefficients.

6 0

2 years ago

Linear equation for (-5,3) and (-1,-1)

Alex787 [66]

Answer:

y = -x - 2

Step-by-step explanation:

y = mx + c

m = (-1-3)/(-1-(-5)) = -4/4 = -1

y = -x + c

(-1,-1)

-1 = -(-1) + c

c = -2

y = -x - 2

6 0

3 years ago

Solve each system by elimination x + 2y = 20 3x +2y = -12

neonofarm [45]

The answer is (2,-9). Hope i can help.

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2 years ago

[tex]\frac{3}{8} of 10x

pentagon [3]

Answer: x = 3/80

Step-by-step explanation:

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2 years ago