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OleMash [197]
3 years ago
10

Which fraction is equivalent to -3/2?

Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0
The correct answer is 3/-2
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A man has 1 coins in his pocket, all of which are dimes and quarters. Aif the total value of his change is $2.75, how many dimes
VLD [36.1K]

Using a system of equations, it is found that there are 5 dimes and 9 quarters in his pocket.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: number of dimes in his pocket.
  • Variable y: number of quarters in his pocket.

He has a total of 14 coins, hence:

x + y = 14 -> y = 14 - x.

They are worth $2.75, hence, considering the value of each coin(dimes $0.1 and quarters $0.25), we have that:

0.1x + 0.25y = 2.75

Since y = 14 - x:

0.1x + 0.25(14 - x) = 2.75

x = (0.25*14 - 2.75)/0.15.

x = 5.

y = 14 - x = 14 - 5 = 9.

There are 5 dimes and 9 quarters in his pocket.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

4 0
2 years ago
Please help!!!!!!!!!!!!!!!
babunello [35]

Answer:

Answer A

Step-by-step explanation:

Answer A indicates some minimal value for the set of points to the left (negative side of the distribution) which are associated with negative skewness since the mean is at 22 also with larger deviation to the left shown in the median of the points to the left further to the negative side of the plot.

Answers B and C show symmetric distributions (no skewness at all).

Answer D would represent skewness to the right (positively skewed)

So the correct answer is answer A.

8 0
3 years ago
Question
bekas [8.4K]

Answer:

y=-1/5x-8/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-(-1))/(2-(-3))

m=(-2+1)/(2+3)

m=-1/5

y-y1=m(x-x1)

y-(-1)=-1/5(x-(-3))

y+1=-1/5(x+3)

y=-1/5x-3/5-1

y=-1/5x-3/5-5/5

y=-1/5x-8/5

7 0
3 years ago
19) Given that f(x)x² - 8x+ 15x² - 25find the horizontal and vertical asymptotes using the limits of the function.A) No Vertical
Tems11 [23]

EXPLANATION

Since we have the function:

f(x)=\frac{x^2-8x+15}{x^2}

Vertical asymptotes:

For\:rational\:functions,\:the\:vertical\:asymptotes\:are\:the\:undefined\:points,\:also\:known\:as\:the\:zeros\:of\:the\:denominator,\:of\:the\:simplified\:function.

Taking the denominator and comparing to zero:

x+5=0

The following points are undefined:

x=-5

Therefore, the vertical asymptote is at x=-5

Horizontal asymptotes:

\mathrm{If\:denominator's\:degree\:>\:numerator's\:degree,\:the\:horizontal\:asymptote\:is\:the\:x-axis:}\:y=0.If\:numerator's\:degree\:=\:1\:+\:denominator's\:degree,\:the\:asymptote\:is\:a\:slant\:asymptote\:of\:the\:form:\:y=mx+b.If\:the\:degrees\:are\:equal,\:the\:asymptote\:is:\:y=\frac{numerator's\:leading\:coefficient}{denominator's\:leading\:coefficient}\mathrm{If\:numerator's\:degree\:>\:1\:+\:denominator's\:degree,\:there\:is\:no\:horizontal\:asymptote.}\mathrm{The\:degree\:of\:the\:numerator}=1.\:\mathrm{The\:degree\:of\:the\:denominator}=1\mathrm{The\:degrees\:are\:equal,\:the\:asymptote\:is:}\:y=\frac{\mathrm{numerator's\:leading\:coefficient}}{\mathrm{denominator's\:leading\:coefficient}}\mathrm{Numerator's\:leading\:coefficient}=1,\:\mathrm{Denominator's\:leading\:coefficient}=1y=\frac{1}{1}\mathrm{The\:horizontal\:asymptote\:is:}y=1

In conclusion:

\mathrm{Vertical}\text{ asymptotes}:\:x=-5,\:\mathrm{Horizontal}\text{ asymptotes}:\:y=1

4 0
1 year ago
How do you do these problems
Elden [556K]

Well for the first one, that is presumably a straight line and straight lines all have 180 degrees. So you add 61 and 23 to get 84 and subtract that from 180. You then get 96 degree.

For the second one corresponding angles on a transversal are congruent so x+95=4x-10 and then you solve the equation.;

For the third one you need to make the change from 9 to 12 be the same as the change from 3 to t. 9 to 12 is 4/3 so 3 times 4/3 is 4. t=4

8 0
3 years ago
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