ANSWER: square root of 10
Rule: Pythagorean Theorem (a^2 + b^2 = c^2; side^2 + second side^2 = hypotenuse^2)
(substitute the missing side w/ a variable)
x^2 + 7^2 = (sqrt. 59)^2
x^2 + 49 = 59
x^2 = 10
x = sqrt. 10
Ac method
for y=ax^2+bx+c
the ac method is normally used for when a≠1
it is used as an aid to help factor
so
0=1x^2-8x+15
multiply a and c (1 times 15=15)
what 2 numbers mulitply to get 15 and add to get -8?
-3 and -5
split the middle up to that
0=1x^2-3x-5x+15
group
0=(x^2-3x)+(-5x+15)
undistribute
0=x(x-3)-5(x-3)
undistribute (x-3)
0=(x-5)(x-3)
set to zero
x-5=0
x=5
x-3=0
x=3
solutions are x= 3 and 5
Answer:
The answer is x=6
Step-by-step explanation:
x=6 is the answer
Hope this helped!
