Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
Answer:
54 m
Step-by-step explanation:
Alrighty, what have we here: an area of 162 m² and a width of 9m.
So: A=162m², W=9m, let's draw this: (see the screenshot attached)
Using the formula for area (Area = width x length) we see that:
Thus: (equating to L by dividing both sides by 9m)
⇒ 
Now we have all of our dimensions, we can use the formula for the perimeter to calculate it:
And there we have our answer.
Answer: O AAS Congruence Theorem is your answer
Step-by-step explanation: plz give brainliest
Here is the answer with an explanation!
