e + 1 13/16 = 2 5/16
subtract 1 13/16 from each side
e = 2 5/16 - 1 13/16
borrow from the 2
e = 1 16/16 + 5 /16 - 1 13/16
e = 1 21/16-1 13/16
e = 1 8 /16
e = 1 1/2
Naturally, any integer

larger than 127 will return

, and of course

, so we restrict the possible solutions to

.
Now,

is the same as saying there exists some integer

such that

We have

which means that any

that satisfies the modular equivalence must be a divisor of 120, of which there are 16:

.
In the cases where the modulus is smaller than the remainder 7, we can see that the equivalence still holds. For instance,

(If we're allowing

, then I see no reason we shouldn't also allow 2, 3, 4, 5, 6.)
Answer:
100:59
Step-by-step explanation:
1 pound = 100pence
59 pence
100:59
9514 1404 393
Answer:
25.5 years
Step-by-step explanation:
The multiplier for continuous compounding at annual rate r for t years is ...
e^(rt)
You want the value of t when that is 3 and r=0.043.
3 = e^(0.043t)
ln(3) = 0.043t
t = ln(3)/0.043 ≈ 25.549 . . . . years
Answer:
x=12
Step-by-step explanation:

the perimeter is the side lengths added together meaning it is
. x+x can be simplified to 2x. now solve for x