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Gala2k [10]
3 years ago
12

Objects 1 and 2 attract each other with a gravitational force

Physics
1 answer:
s344n2d4d5 [400]3 years ago
4 0

The new gravitational force will be 9 units

Explanation:

The magnitude of the gravitational force between two objects is given by

F=\frac{Gm_1 m_2}{r^2}

where

G is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the distance separating the two objects

Let's call

F = 36 units

the initial gravitational force between the two objects here, when they are separated by a distance r.

Later, the distance is doubled, so

r' = 2r

So the new force is

F'=\frac{Gm_1 m_2}{r'^2}=\frac{Gm_1 m_2}{(2r)^2}=\frac{1}{4} (\frac{Gm_1 m_2}{r^2})=\frac{1}{4}F

So, the gravitational force has decreased by a factor 4, and therefore the new value is

F'=\frac{36}{4}=9 units

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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A 6 kg bowling ball moves with a speed of 3 m/s. How fast does a 7 kg bowling ball need to move so that it has the same kinetic
maw [93]

Answer: 7 kg bowling ball must move with a speed of 2.8 m/s so that it has the same kinetic energy.

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion.

K.E=\frac{1}{2}mv^2

m = mass of object

v= velocity of the object

K.E=\frac{1}{2}\times 6kg\times (3m/s)^2=27Joules

b) for a 7 kg bowl to have kinetic energy of 27 Joules:

27J=\frac{1}{2}\times 7kg\times v^2

v^2=7.7

v=2.8m/s

Thus 7 kg bowling ball must move with a speed of 2.8 m/s so that it has the same kinetic energy

4 0
3 years ago
NEED HELP!!!! 15 POINTS!!!!!!!
telo118 [61]
I believe A is the correct answer!!
8 0
3 years ago
A coil has N turns enclosing an area of A. In a physics laboratory experiment, the coil is rotated during the time interval Δt f
scoray [572]

Answer:

BA

0

\dfrac{NBA}{\Delta t}

Explanation:

B = Magnetic field

A = Area

\theta = Angle

t = Time taken

Before rotation the magnetic flux is given by

\phi_i=BAsin\theta\\\Rightarrow \phi_i=BAsin90\\\Rightarrow \phi_i=BA

Magnetic flux is BA

After rotation the magnetic flux is given by

\phi_i=BAsin\theta\\\Rightarrow \phi_i=BAsin0\\\Rightarrow \phi_i=0

The magnetic flux is 0

Magnitude of emf is given by

\epsilon=NA\dfrac{d\phi}{dt}\\\Rightarrow \epsilon=\dfrac{NBA}{\Delta t}

The magnitude of the average emf induced in the entire coil is \dfrac{NBA}{\Delta t}

4 0
3 years ago
What is field in physics​
Troyanec [42]
Where everything is effected by a force
6 0
3 years ago
In a compressional wave the denser the medium is at the compressions the smaller is amplitude?
svlad2 [7]
Wellll, let me think about that ...

I don't think I'd agree that you can characterize the amplitude of
a wave according to the density at only one point in it.  After all ...
a tiny wave in steel would be much denser at a compression than
a huge wave in air would be.

The amplitude of any wave is described as the difference between
a peak and the resting value.  Or even better ... half of the difference
between a maximum and a minimum.

So if you're looking at a longitudinal wave, like sound, I'd say if you
want to describe its amplitude, then you have to look at the density
at two points ... either the difference between the compression and
the resting densities, or the difference between the greatest compression
and the greatest rarefaction. 

That's my opinion.  I could be wrong.
5 0
3 years ago
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