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Gala2k [10]
3 years ago
12

Objects 1 and 2 attract each other with a gravitational force

Physics
1 answer:
s344n2d4d5 [400]3 years ago
4 0

The new gravitational force will be 9 units

Explanation:

The magnitude of the gravitational force between two objects is given by

F=\frac{Gm_1 m_2}{r^2}

where

G is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the distance separating the two objects

Let's call

F = 36 units

the initial gravitational force between the two objects here, when they are separated by a distance r.

Later, the distance is doubled, so

r' = 2r

So the new force is

F'=\frac{Gm_1 m_2}{r'^2}=\frac{Gm_1 m_2}{(2r)^2}=\frac{1}{4} (\frac{Gm_1 m_2}{r^2})=\frac{1}{4}F

So, the gravitational force has decreased by a factor 4, and therefore the new value is

F'=\frac{36}{4}=9 units

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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A teenager of mass m1 = 72 kg pushes backward against the ground with his foot as he rides his skateboard. This exerts a horizon
Ray Of Light [21]

Answer:

The acceleration of the skateboard is -9.65 m/s².

Explanation:

Given that,

Mass of teenager = 72 kg

Force F_{foot}=11\ N

Mass of skateboard = 2.8 kg

Suppose, the determine the numerical value for the magnitude of the acceleration of skateboard

We need to calculate the acceleration of skateboard

Using balance equation

F-(m_{1}+m_{2})g=(m_{1}+m_{2})a

Put the value into the formula

11-(72+2.8)\times9.8=(72+2.8)\times a

a=\dfrac{11-(72+2.8)\times9.8}{(72+2.8)}

a=-9.65\ m/s^2

Hence, The acceleration of the skateboard is -9.65 m/s².

5 0
3 years ago
todos los cuerpos pueden estar sobre la tierra por la fuerza de gravedad .cuando nos caemos ,saltamos y realizamos otras activid
const2013 [10]
¿Es esta una pregunta verdadera o falsa? Por cierto, no hay mucha gente que hable español en esta aplicación, así que buena suerte.
4 0
3 years ago
After a large snowstorm, you shovel 2,500 kilograms of snow off of your sidewalk in half an hour. You lift
Delvig [45]
Well, the snow has a total weight G=mg=25,000 N. The work is L=Fd=Gh=1.5*25,000=37,500 J. The power is L/t, where t=1800 seconds. P=37,500/1800=20.833 W.
3 0
3 years ago
A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. W
Tamiku [17]
<h2>Answer</h2>

Radius is 421 m.

<u>Explanation </u>

A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. Therefore, for radius we use formula which is Fc = mv ^ 2 / r,

As mass = m = 1500kg,

Centripetal force = Fc = 640N,

Velocity = v = 13.4 m / s

By putting values, Fc = mv ^ 2 / r,

r = mv ^ 2 / Fc,

=> r = ( 1500kg ) . ( 13.4 m / s) ^ 2 / 640,

=> r = ( 1500kg ) . ( 179.56 ) / 640,

r = 269340 / 640,

=> r = 420.84 m.

Radius is 421 m.

8 0
3 years ago
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