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3 years ago

Describe the evolution of a pulsar over time, in particular how the rotation and pulse signal changes over time.

Physics

1 answer:

madam [21]3 years ago

3 0

Answer:

As beams of particles and their associated energy are given off, the pulsar will lose energy slowly, which will decrease the rate of its rotation. The frequency of pulses would therefore decrease, so that fewer pulses are observed in a given time span. The strength of the pulse signal will also decrease so the pulses will become fainter. Eventually, the pulsar should rotate so slowly and have such a low emission of radiation that it would no longer be observable.

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A 1-kg iron frying pan is placed on a stove. The pan increases from 20°C to 250°

timurjin [86]

Answer;

The temperature change for the second pan will be lower compared to the temperature change of the first pan

Explanation;

-The quantity of heat is given by multiplying mass by specific heat and by temperature change.

That is; Q = mcΔT

This means; the quantity of heat depends on the mass, specific heat capacity of a substance and also the change in temperature.

-Maintaining the same quantity of heat, with another pan of the same mass and greater specific heat capacity would mean that the change in temperature would be much less lower.

8 0

3 years ago

Read 2 more answers

Enzyme reaction and deactivation Lipase is being investigated as an additive to laundry detergent for removal of stains from fab

natita [175]

Answer:

t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]

Explanation:given values

Half life of lipase t_1/2 = 8 min x 60s/min = 480 s

Rate constant for first order reaction

k_d = 0.6932/480 = 1.44 x 10^-3 s-1

Initial fat concentration S_0 = 45 mol/m3 = 45 mmol/L

rate of hydrolysis Vm0 = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration S = S_0(1-X) = 45 (1-0.80) = 9 mol/m3

K_m = 5mmol/L

time take is given by

$t= -\frac{1}{K_d}ln[1-\frac{K_d}{V_m_0}(k_mln\frac{s_0}{s}+(s_0-s))]$

all values are given and putting these value we get

t=1642.83 secs

which is equal to

t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]

5 0

2 years ago

What is needed to give a larger boulder a large acceleration?

Ronch [10]

More force needs to be applied

7 0

3 years ago

Read 2 more answers

If the speed of light in a substance is 2.26 x 10^8 m/s, what is the index of refraction of that substance?

vladimir1956 [14]

Answer:

1.33

Explanation:

speed of light in vacuum, c = 3 x 10^8 m/s

speed of light in medium, v = 2.26 x 10^8 m/s

The refractive index of the medium is given by

μ = speed of light in vacuum / speed of light in medium

μ = (3 x 10^8) / (2.26 x 10^8)

μ = 1.33

4 0

2 years ago

A rigid tank contains air at a pressure of 70 psia and a temperature of 55 ˚F. By how much will the pressure increase as the tem

Katyanochek1 [597]

Answer:

P_2 = 62.69 psi

Explanation:

given,

P₁ = 70 psia T₁ = 55° F = (55 + 459.67) R

P₂ = ? T₂ = 115° F = (115 + 459.67) R

we know,

p = ρ RT

ρ is the density which is constant

R is also constant

now,

$\dfrac{P_2}{P_1} =\dfrac{T_2}{T_1}$

$\dfrac{P_2}{70} =\dfrac{55+459.67}{115+459.67}$

P_2 = 62.69 psi

Hence, the increase in Pressure is equal to P_2 = 62.69 psi

7 0

2 years ago