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3 years ago

9

If an object is not accelerating, how many forces act on it?

2 answers:

poizon [28]3 years ago

8 0

Answer:

If there are no forces acting upon the object, then there is no acceleration. If there is no acceleration, then the object will move with a constant velocity.

Explanation:

Ann [662]3 years ago

3 0

If an object is not accelerating, then zero net forces act on the object.

<u>Explanation: </u>

As per Newton's second laws of motion, an object exhibiting acceleration is directly proportionate to the net forces act on the objects and inversely proportionate to the object's mass.

But object's mass cannot be zero, so if the acceleration is zero for an object, the total forces act on that object will be zero. And for zero net force to occur, two equal but opposite forces are enough to nullify the net force. Thus if an object does not accelerate, then zero net force acts on the object.

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When salt and water are mixed, they form a solution like in the ocean. When sand and water are mixed, they form a mixture where

Yuliya22 [10]

Answer:

D

Explanation:

The answer is D. Solutions you cannot see the separate substances. however in a mixture you can see the different substances. So the correct choice is D

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Three-fourths of the elements on the

77julia77 [94]

Answer:

b

Explanation:

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What burns quicker, white or colored candles?

VashaNatasha [74]

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3 years ago

Andrea's near point is 20.0 cm and her far point is 2.0 m. Her contact lenses are designed so that she can see objects that are

Shalnov [3]

Answer:

the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

Explanation:

Given the data in the question,

near point = 20 cm

far point = 2 m = 200 cm

Now, for an object that is infinitely far away, the image is at is its far point.

so using the following expression, we can determine the focal length

1/f = 1/i + 1/o

where f is the focal length, i is the image distance and o is the object distance.

here, far point i = 2 m = 200 cm and v is ∞

so we substitute

1/f = 1/(-200 cm) + 1/∞

f = -200 cm

Also, for object at its closest point, the image appear at near point,

so

1/f = 1/i + 1/o

we make o the subject of formula

o = ( i × f ) / ( i - f )

given that near point i = 20 cm

we substitute

o = ( -20 × -200 ) / ( -20 - (-200) )

o = 4000 / 180

o = 22.2 cm

Therefore, the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

4 0

3 years ago

A thin rod of length 1.4 m and mass 140 g is suspended freely from one end. It is pulled to one side and then allowed to swing l

m_a_m_a [10]

Answer:

a The kinetic energy is $KE = 0.0543 J$

b The height of the center of mass above that position is $h = 1.372 \ m$

Explanation:

From the question we are told that

The length of the rod is $L = 1.4m$

The mass of the rod $m = 140 = \frac{140}{1000} = 0.140 \ kg$

The angular speed at the lowest point is $w = 1.09 \ rad/s$

Generally moment of inertia of the rod about an axis that passes through its one end is

$I = \frac{mL^2}{3}$

Substituting values

$I = \frac{(0.140) (1.4)^2}{3}$

$I = 0.0915 \ kg \cdot m^2$

Generally the kinetic energy rod is mathematically represented as

$KE = \frac{1}{2} Iw^2$

$KE = \frac{1}{2} (0.0915) (1.09)^2$

$KE = 0.0543 J$

From the law of conservation of energy

The kinetic energy of the rod during motion = The potential energy of the rod at the highest point

Therefore

$KE = PE = mgh$

$0.0543 = mgh$

$h = \frac{0.0543}{9.8 * 0.140}$

$h = 1.372 \ m$

5 0

3 years ago

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