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3 years ago

9

If an object is not accelerating, how many forces act on it?

2 answers:

poizon [28]3 years ago

8 0

Answer:

If there are no forces acting upon the object, then there is no acceleration. If there is no acceleration, then the object will move with a constant velocity.

Explanation:

Ann [662]3 years ago

3 0

If an object is not accelerating, then zero net forces act on the object.

<u>Explanation: </u>

As per Newton's second laws of motion, an object exhibiting acceleration is directly proportionate to the net forces act on the objects and inversely proportionate to the object's mass.

But object's mass cannot be zero, so if the acceleration is zero for an object, the total forces act on that object will be zero. And for zero net force to occur, two equal but opposite forces are enough to nullify the net force. Thus if an object does not accelerate, then zero net force acts on the object.

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Earthquakes often occur along _____ as a result of the build up of stress

ExtremeBDS [4]

Hello Lauren, The answer to this question is D:Plate boundaries.

Have a wonderful day:).

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3 years ago

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A block is released from the top of a frictionless incline plane as pictured above. If the total distance travelled by the block

kotegsom [21]

Complete Question

The diagram for this question is showed on the first uploaded image (reference homework solutions )

Answer:

The velocity at the bottom is $v = 11.76 \ m/ s$

Explanation:

From the question we are told that

The total distance traveled is $d = 1.2 \ m$

The mass of the block is $m_b = 0.3 \ kg$

The height of the block from the ground is h = 0.60 m

According the law of energy

$PE = KE$

Where PE is the potential energy which is mathematically represented as

$PE = m * g * h$

substituting values

$PE = 3 * 9.8 * 0.60$

$PE = 17.64 \ J$

So

KE is the kinetic energy at the bottom which is mathematically represented as

$KE = \frac{1}{2} * m v^2$

So

$\frac{1}{2} * m* v ^2 = PE$

substituting values

=> $\frac{1}{2} * 3 * v ^2 = 17.64$

=> $v = \sqrt{ \frac{ 17.64}{ 0.5 * 3 } }$

=> $v = 11.76 \ m/ s$

4 0

3 years ago

A car has a mass of 1300 kg and a velocity of 15 m/s. The car crashes into a wall and stops in two seconds. What is the stopping

Musya8 [376]

Answer:

B

Explanation:

Newton's second law:

F = ma

The acceleration is Δv/Δt, so:

F = m Δv/Δt

Given m = 1300 kg, Δv = 15 m/s, and Δt = 2 s:

F = (1300 kg) (15 m/s) / (2 s)

F = 9750 N

Answer B.

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3 years ago

An object of height 2.4 cm is placed 29 cm in front of a diverging lens of focal length 19 cm. Behind the diverging lens, and 11

Arada [10]

Answer:

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Explanation:

Given tgat:

Object distance, u = 29 cm

Image distance, v =

Focal length, f = - 19 (diverging lens)

Mirror formula :

1/u + 1/v = 1/f

1/29 + 1/v = - 1/19

1/v = - 1/19 - 1/29

1/v = −0.087114

v = −11.47916

v = -11.48

Second lens

Object distance :

u = 11.48 + 11 = 22.48 cm

1/v = 1/19 - 1/22.48

1/v = 0.0081475

v = 1 / 0.0081475

v = 122.735 cm

122.735 behind second lens

Magnification, m

m = m1 * m2

m = - v / u

Lens1 :

m1 = -11.48 / 29 = - 0.3958620

m2 = - 122.735 / 22.48 = - 5.4597419

Hence,

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3 years ago

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labwork [276]

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3 years ago