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kenny6666 [7]
3 years ago
6

A teenager of mass m1 = 72 kg pushes backward against the ground with his foot as he rides his skateboard. This exerts a horizon

tal force of magnitude Ffoot = 11 N. The skateboard has m2 = 2.8 kg.
Physics
1 answer:
Ray Of Light [21]3 years ago
5 0

Answer:

The acceleration of the skateboard is -9.65 m/s².

Explanation:

Given that,

Mass of teenager = 72 kg

Force F_{foot}=11\ N

Mass of skateboard = 2.8 kg

Suppose, the determine the numerical value for the magnitude of the acceleration of skateboard

We need to calculate the acceleration of skateboard

Using balance equation

F-(m_{1}+m_{2})g=(m_{1}+m_{2})a

Put the value into the formula

11-(72+2.8)\times9.8=(72+2.8)\times a

a=\dfrac{11-(72+2.8)\times9.8}{(72+2.8)}

a=-9.65\ m/s^2

Hence, The acceleration of the skateboard is -9.65 m/s².

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