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Sophie [7]
3 years ago
5

Can you solvefor x 3 (x+4)+5x=-20

Mathematics
1 answer:
inn [45]3 years ago
3 0
Solve for x:5 x + 3 (x + 4) = -20
3 (x + 4) = 3 x + 12:3 x + 12 + 5 x = -20
Grouping like terms, 5 x + 3 x + 12 = (5 x + 3 x) + 12:(5 x + 3 x) + 12 = -20
5 x + 3 x = 8 x:8 x + 12 = -20
Subtract 12 from both sides:8 x + (12 - 12) = -12 - 20
12 - 12 = 0:8 x = -20 - 12
-20 - 12 = -32:8 x = -32
Divide both sides of 8 x = -32 by 8:(8 x)/8 = (-32)/8
8/8 = 1:x = (-32)/8
The gcd of -32 and 8 is 8, so (-32)/8 = (8 (-4))/(8×1) = 8/8×-4 = -4:Answer: x = -4
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Now, because f(0)=5, 5=0^4 + 0^3 -2(0)^2 + C(0) + D, so that D=5.
Determine D in the same manner:  Let x=1 and find the value of C.

Then the solution, f(x), is x^4 + x^3 - 2x^2 + Cx + 5.  Replace C with this value and then you'll have the desired function f(x).</span>
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