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elena-14-01-66 [18.8K]
4 years ago
10

Which diagram correctly shows how triangles are classified

Mathematics
1 answer:
topjm [15]4 years ago
4 0

Step-by-step explanation:

I do not see your diagram. Triangles can be isosceles, scalene, equilateral, degenerate, etc.

Isosceles; 2 congruent sides and angles

Scalene: no congruent sides and angles

Equilateral: 3 congruent sides and angles

Degenerate: The sum of two sides is equal to the length of the other one, looks like a line segment.

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Your friend has given you a map that he drew of your neighborhood for a class project. Before he turns it in, he asks you to che
balandron [24]

Answer:

Step-by-step explanation:

A accurate map should be to scale. Scaled distances between features should agree with actual distances. The shapes of objects (eg houses) should be the same as in real life. All road names names and house numbers etc should be displayed.  

However, to create such a map would need considerable expertise. It would be unreasonable to expect someone to produce it for a class project.  

It would be useful if it was roughly to scale with houses shown in approximate positions and shapes. Names and numbers are essential. It would be useful to show North.

7 0
3 years ago
A figure is reflected across the x-axis to create a new figure. Which rule describes this transformation?
tangare [24]

Answer:

f(x) reflected across the x-axis is -f(x)

Step-by-step explanation:

so aka

O (x,y) → (x, -y)

8 0
3 years ago
Look at this cone:<br><br>,,
Assoli18 [71]
  • Slant height=l=3ft
  • Radius=r=2ft

We know

\boxed{\sf \star TSA_{(Cone)}=\pi r(r+\ell)}

\\ \sf\longmapsto TSA_{(Old\:Cone)}=2 \dfrac{22}{7}\times 2(2+3)

\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{44}{7}(5)

\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{220}{7}

\\ \sf\longmapsto TSA_{(Old\:Cone)}=31.4ft^2

Now

  • New slant height =2(3)=6cm
  • New radius=2(2)=4cm

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{22}{7}\times 4(4+6)

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{88}{7}(10)

\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{880}{7}

\\ \sf\longmapsto TSA_{(New\:Cone)}=125.7cm^2

So

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{125.7}{31.4}

\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{4}{1}

\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cone)}}:{TSA_{(Old\:Cone)}}=4:1}}}

7 0
3 years ago
Let f(x)=20/1+9e^3x .
Alex777 [14]
The answer is the last one
6 0
3 years ago
Read 2 more answers
Anyone want to help me!?!?!?!
Tresset [83]

Answer:

368 in^2

Step-by-step explanation:

To find the entire surface area, do the following:

Find the area of the base and then multiply it by 2:

(6 in)(5 in)(2) = 60 in^2

Find the area of one side and then mult. it by 2:  then find the area of the other side and mult. that by 2 also.  Add together these 3 results:

(6 in)(14 in)(2) + (5 in)(14 in)(2) + 60 in^2 = 368 in^2

7 0
3 years ago
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