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gavmur [86]
3 years ago
8

Can someone help me

Mathematics
1 answer:
Daniel [21]3 years ago
3 0
Y=10x+8
8 is the y intercept because it’s when x=0
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-120 degrees is equal to what?
hichkok12 [17]

It's not clear what you're looking for.

If you want to find an angle whose terminal point involves a positive angle, then -120 degrees is equivalent to +240 degrees.

If you want the equivalent angle in radians, then:

-120 deg        -π rad

-------------- = --------------- =  - 2π/3 rad, or + 4π/3 rad.

      1              180 deg

4 0
4 years ago
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In how many ways can a
swat32

Answer:

720

Step-by-step explanation:

Using the equation given

\frac{6!}{(6-6)!}=\frac{6!}{0!}=\frac{6!}{1}=720

3 0
3 years ago
12) -7(-8 + y - 10 – x); use x = -3, and y = 10<br> A) 35<br> B) 40<br> C) 34<br> D) 25
cluponka [151]

Answer:

A

Step-by-step explanation:

56-70+70-21

126-91

35

5 0
4 years ago
5.125 divided by 7.1
Olegator [25]

Answer:

0.72

Step-by-step explanation:

8 0
3 years ago
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A truck loaded with 8000 electronic circuit boards has just pulled into a firm’s receiving dock. The supplier claims that no mor
Juliette [100K]

Answer:

The 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

Let <em>X</em> = number of boards that fall outside the most rigid level of industry performance specifications.

In a random sample of 300 boards the number of defective boards was 12.

Compute the sample proportion of defective boards as follows:

\hat p =\frac{12}{300}=0.04

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The critical value of <em>z</em> for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

3 0
3 years ago
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