Average amount of time wind machines operate
1 answer:
The wind machine on an average operates for a time of about .
Explanation:
The wind energy is the method of using the energy carried by the wind to generate the power. The wind energy is the considered as the conventional and clean source of energy.
The wind machines require the high power winds to rotate the blades of the windmill and produce power using the energy of the moving wind.
The winds blow at such high speed for a very small time during the day, the wind machine cannot be expected to work for a longer time during the whole day.
The wind energy can be obtained form a wind mill for a limited time unlike the other form of energy like thermal energy or even the solar energy. The thermal energy can be obtained at anytime due to burning of fuel whereas the solar energy can at least be obtained during the whole day time.
Thus, the wind machine on an average operates for a time of about .
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1. Acceleration of the box under friction brainly.com/question/7031524
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Answer Details:
Grade: Middle School
Subject: Physics
Chapter: Energy
Keywords:
wind energy, conventional source, energy, thermal, solar, 3-4 hours, high speed, machine, time, operate.
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The kinetic energy possessed by the man is 517.5 Joules.
<u>Given the following data:</u>
- Mass = 90.0 kg
- Velocity = 11.5 m/s.
To find the kinetic energy of the man:
Kinetic energy is an energy that is possessed by a physical object or body due to its motion.
Mathematically, kinetic energy is calculated by using the formula;
<u>Where:</u>
- K.E is the kinetic energy.
- M is the mass of an object.
- V is the velocity of an object.
Substituting the given values, we have;
×
×
×
<em>Kinetic energy = 517.5 Joules.</em>
Therefore, the kinetic energy possessed by the man is 517.5 Joules.
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Answer: after 1.75 seconds
Explanation:
The only force acting on the ball is the gravitational force, so the acceleration will be:
a = -9.8 m/s^2
the velocity can be obtained by integrating over time:
v = -9.8m/s^2*t + v0
where v0 is the initial velocity; v0 = -7.95 m/s.
v = -9.8m/s^2*t - 7.95 m/s.
For the position we integrate again:
p = -4.9m/s^2*t^2 - 7.95 m/s*t + p0
where p0 is the initial position: p0 = 29m
p = -4.9m/s^2*t^2 - 7.95 m/s*t + 29m
Now we want to find the time such that the position is equal to zero:
0 = -4.9m/s^2*t^2 - 7.95 m/s*t + 29m
Then we solve the Bhaskara's equation:
Then the solutions are:
t = (7.95 + 25.1)/(-9.8) = -3.37s
t = (7.95 - 25.1)/(-9.8) = 1.75s
We need the positive time, then the correct answer is 1.75s