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3 years ago

9

By what primary method of heat transfer does the sun warm the earth?

1 answer:

GenaCL600 [577]3 years ago

5 0

Sun warms the earth with Electromagnetic Radiations.

Sun emits out short range radiation in the form of Electromagnetic (EM) Radiation. Our Atmosphere is transparent to EM radiation. It does not heats up the atmosphere but when it collide with the solid objects or particles it is absorbed, reflected or refracted and the object heats up and start emitting radiation in the form of long wave radiation. Our Earth does the same. The long wave radiation emitted by the earth surface is absorbed by our atmosphere and it heats up. Therefore, we can say our atmosphere is heated from below.

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Using Kepler's 3rd law and Newton's law of universal gravitation, find the period of revolution P of the planet as it moves arou

weeeeeb [17]

Answer:

$P = \pi \sqrt{\frac{(R_1+R_2)^3}{2 \ GMS}}$

Explanation:

From the attached diagram below:

AC = a (1 + e) = R₂ -------- equation (1)

CD = a ( 1 - e) = R₁ --------- equation (2)

⇒ 1 - e = $\frac{R_1}{a}$

$e= 1 - \frac{R_1}{a}$

Replacing the value for e into equation (1)

$a(1+1- \frac{R_1}{a})= R_2$

$= 2a - R_1 = R_2$

$a= \frac{R_1+R_2}{2}$

From Kepler's third law;

$P = 2 \pi \sqrt{\frac{a^3}{GMS}}$

$P = 2 \pi \sqrt{\frac{(R_1+R_2)^3}{8GMS}}$

$P = \pi \sqrt{\frac{(R_1+R_2)^3}{2 \ GMS}}$

5 0

3 years ago

(b) Which has more mass: 50 cm of gold or 50 cm of aluminum? Explain.

monitta

Gold’s molar mass is about 196 while aluminum is about 27, thus 50cm of gold has more mass

8 0

3 years ago

: Consider a transformer used to recharge rechargeable flashlight batteries, that has 500 turns in its primary coil, 4 turns in

Aneli [31]

Answer:

a) 096V b) 0.0288A c) 0.3456W

Explanation:

a) Vp/Vs= Np/Ns

120/Vs= 500/4

Vs= 096V

b) Np/Ns= Is/Ip

500/4= 3.6/Ip

Ip= 0.0288A

c) P= VI

P=(120)(0.0288)

P= 0.3456W

8 0

3 years ago

Consider two identical microscope slides in air illuminated with monochromatic light. the bottom slide is rotated (counterclockw

vlabodo [156]

Answer:

Explanation:ruhfu

4 0

4 years ago

A Ca atom (atomic number = 20) is in the ground state. Light is shined on the atom, exciting the most energetic electron. Which

Vikentia [17]

Answer:

The possible quantum numbers for Ca atom when it is in excited

n = 4

l= 1

m =-1,0,1

Explanation:

Given that,

Atomic number = 20

The configuration of Ca

$Ca = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2$

So, The principle quantum number is n =4.

The azimuthal quantum number can take value from 0,1,2...(n-1)

In the ground state, l= 0

When it is excited to p state

Then, l = 1

The magnetic quantum number can take value from l to -l

$m=1,0,-1$

Hence, The possible quantum numbers for Ca atom when it is in excited

n = 4

l= 1

m =-1,0,1

4 0

3 years ago