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lutik1710 [3]
3 years ago
14

How to calculate variance of negative binomial distribution?

Mathematics
2 answers:
allsm [11]3 years ago
6 0
This was not my question I needed help in solving out the coefficient of the variable

1/2d + 6
victus00 [196]3 years ago
3 0
Var(y)=k(1-p)/p^2
where y is the random variable
k is the successes obtain from y
0<p<1
You might be interested in
Need help ASAP!!!!!!!
natima [27]

Answer:

A

Step-by-step explanation:

You can subtract normally when the square roots are the same( like in your problem) but the squares stay they same and the numbers on the outside change.

4 0
3 years ago
Read 2 more answers
What expression shows 4 less than a number?<br> A. n + 4<br> B. n - 4<br> C. 4 - n<br> D. n(4)
Elis [28]

Answer:

B

Step-by-step explanation:

Because the expression in b is saying whatever number n is say 9 then your subtracting 4 by N or like I said take 9 for an example which=5

hope it helps

3 0
2 years ago
Read 2 more answers
How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

4 0
2 years ago
Help plz!!!
lara [203]

Answer with explanation:

→→→Function 1

f(x)= - x²+ 8 x -15

Differentiating once , to obtain Maximum or minimum of the function

f'(x)= - 2 x + 8

Put,f'(x)=0

-2 x+ 8=0

2 x=8

Dividing both sides by , 2, we get

x=4

Double differentiating the function

f"(x)= -2, which is negative.

Showing that function attains maximum at ,x=4.

Now,f(4)=-4²+ 8× 4-15

           = -16 +32 -15

          = -31 +32

          =1

→→→Function 2:

f(x) = −x² + 2 x − 3

Differentiating once , to obtain Maximum or minimum of the function

f'(x)= -2 x +2

Put,f'(x)=0

-2 x +2=0

2 x=2

Dividing both sides by , 2, we get

x=1

Double differentiating the function,gives

f"(x)= -2 ,which is negative.

Showing that function attains maximum at ,x=1.

f(1)= -1²+2 ×1 -3

   = -1 +2 -3

  = -4 +2

 = -2

⇒⇒⇒Function 1  has the larger maximum.

6 0
3 years ago
Suppose we want to test the claim that less than ½ of Americans are in favor of raising the voting age to 21. Is the hypothesis
d1i1m1o1n [39]
Two tailed ..? Lol I haven’t learned this yet but I am taking a guess what two tailed
4 0
3 years ago
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