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kifflom [539]
2 years ago
9

Which expression is equivalent to (3 x^ 2 - 7)​

Mathematics
1 answer:
Kay [80]2 years ago
5 0

Answer:

What are the posible answers for the question?

Step-by-step explanation:

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Is 5x-7y=3 standard form?
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Yes it is. Ax+By=C is standard form. :)
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F the price of a pair of shoes is $35.00 before tax, and tax is 20%, what will the final price of the pair of shoes be?
azamat

Answer:

$42

Step-by-step explanation:

35·0.20=7

tax is $7

35+7=42

the final price is $42

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3 years ago
Is (a + b) and (a - b)? perfect square trinomials?<br> O True<br> O False
lisabon 2012 [21]

Answer:

False

Step-by-step explanation:

Pos and negs cannot be perfect square trinomials

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each glass of lemonade costs 1 1/2 times the cost of each glass of orange juice

Step-by-step explanation:

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3 years ago
Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
2 years ago
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